【Python】实现MATLAB中计算两个矩形相交面积的rectint函数

1 rectint函数

A 和 B 是一个思维向量 [x,y,width,height]

area = rectint(A,B)

2 Python实现

class Rectangle:
    def __init__(self, x, y,w,h):
      self.x = x
      self.y = y
      self.width = w
      self.height = h
ra = Rectangle(3., 3., 5., 5.)
rb = Rectangle(1., 1., 4., 4.)
# intersection here is (3, 3, 4, 3.5), or an area of 1*.5=.5

def calc_area(rect1, rect2):
    xl1, yb1, xr1, yt1 = rect1.x,rect1.y,rect1.x+rect1.width,rect1.y+rect1.height 
    # （xl1, yb1）为矩形左下角坐标， （xr1, yt1）为右上角坐标
    xl2, yb2, xr2, yt2 = rect2.x,rect2.y,rect2.x+rect2.width,rect2.y+rect2.height 
    # （xl2, yb2）为矩形左下角坐标， （xr2, yt2）为右上角坐标
    xmin = max(xl1, xl2)
    ymin = max(yb1, yb2)
    xmax = min(xr1, xr2)
    ymax = min(yt1, yt2)
    width = xmax - xmin
    height = ymax - ymin
    if width <= 0 or height <= 0:
        return 0
    cross_square = width * height
    return cross_square

print(area(ra, rb))
# 4.0