Given a list of words, we may encode it by writing a reference string S and a list of indexes A.
For example, if the list of words is ["time", "me", "bell"], we can write it as S = "time#bell#" and indexes = [0, 2, 5].
Then for each index, we will recover the word by reading from the reference string from that index until we reach a "#" character.
What is the length of the shortest reference string S possible that encodes the given words?
Example:
Input: words = ["time", "me", "bell"]
Output: 10
Explanation: S = "time#bell#" and indexes = [0, 2, 5].
Note:
1 <= words.length <= 2000.
1 <= words[i].length <= 7.
Each word has only lowercase letters.
来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/short-encoding-of-words
著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

本题采用 LeetCode 的官方题解，记录如下：
class Solution:
    def minimumLengthEncoding(self, words: List[str]) -> int:
        good = set(words)
        for word in words:
            for k in range(1, len(word)):
                good.discard(word[k:])
        return sum(len(word) + 1 for word in good)
作者：LeetCode-Solution
链接：https://leetcode-cn.com/problems/short-encoding-of-words/solution/dan-ci-de-ya-suo-bian-ma-by-leetcode-solution/
来源：力扣（LeetCode）
著作权归作者所有。商业转载请联系作者获得授权，非商业转载请注明出处。