清览题库
题号：20241
#include <stdio.h> int main() { double areaT(double r,double h);//对areaT函数进行声明 double r,h,v; printf("请输入半径和高："); scanf("%lf%lf",&r,&h);//输入double类型数据，必须使用%lf，不可以%f v=areaT(r,h); printf("r=%f\n",r); printf("h=%f\n",h); printf("v=%.2f\n",v);//输出结果保留两位小数 return 0; } double areaT(double r,double h) { double z; z=h*3.14*r*r/3; return(z);//返回结果语法 }
20242
#include <stdio.h> int main() { double areaT(double a,double b,double h); double a,b,h,s; scanf("%lf%lf%lf",&a,&b,&h);//带上取地址符&！！！！！！ s=areaT(a,b,h);//后面有分号 printf("%.2f",s); return 0; } double areaT(double a,double b,double h) { double z; z=(a+b)*h/2; return(z); }
20251----待修改
#include <stdio.h> int main() { int arr[3],i,j; for(i=0;i<=2;i++) scanf("%d",&arr[i]); for(i=0;i<2;i++) { for(j=0;j<2-i;j++){ if(arr[i]>arr[i+1]) { int t; t=arr[i+1]; arr[i+1]=arr[i]; arr[i]=t; } } } for(i=0;i<=2;i++) printf("%d\t",arr[i]); return 0; }
答案
#include <stdio.h> int main() { void swap( int *p1, int *p2 ); int n1, n2, n3; int *p1, *p2, *p3; scanf( "%d %d %d", &n1, &n2, &n3 ); p1 = &n1; p2 = &n2; p3 = &n3; if ( n1 > n2 ) swap( p1, p2 ); if ( n1 > n3 ) swap( p1, p3 ); if ( n2 > n3 ) swap( p2, p3 ); printf( "%d %d %d\n", n1, n2, n3 ); return(0); } void swap( int *p1, int *p2 ) { int p; p = *p1; *p1 = *p2; *p2 = p; }
20229
#include <stdio.h> int main() { double sum(double a,double b); double a,b,s; scanf("%lf%lf",&a,&b); s=sum(a,b); printf("%.2f",s); return 0; } double sum(double a,double b) { double z; z=a+b; return(z); }
20133
#include <stdio.h> int main() { int x; for(x=0;x<3000;x++) if(x%5==1&&x%6==5&&x%7==4&&x%11==10){ printf("%d",x); } return 0; }
20275
#include <stdio.h> int main() { void nav(int *q1,int *q2); int a,b,*p1,*p2; printf("请输入a和b:"); scanf("%d%d",&a,&b); p1=&a; p2=&b; nav(p1,p2); printf("max=%d,min=%d",*p1,*p2); return 0; } void nav(int *q1,int *q2) { if(*q1<*q2) { int temp; temp=*q1; *q1=*q2; *q2=temp; } }
20276
方法一
#include <stdio.h> int a, b, c; int main() { void nav(int q1, int q2, int q3); scanf("%d%d%d", &a, &b, &c); nav(a, b, c); printf("%d %d %d", a, b, c); return 0; } void nav(int q1, int q2, int q3) { void rev(int x, int y); if (q1 < q2) { int temp; temp = a; a = b; b = temp; } if (q1 < q3) { int temp; temp = a; a = c; c = temp; } if (q2 < q3) { int temp; temp = c; c = b; b = temp; } }
方法二
#include <stdio.h> int main() { void exchange(int *q1,int *q2,int *q3); int a,b,c,*p1,*p2,*p3; printf("请输入a,b,c的值:"); scanf("%d%d%d",&a,&b,&c); p1=&a; p2=&b; p3=&c; exchange(p1,p2,p3); printf("由小到大的排序为%d,%d,%d",a,b,c); printf("%d,%d,%d",*p1,*p2,*p3);//指针指向并没有改变,改变的为a,b,c的值 return 0; } void exchange(int *q1,int *q2,int *q3)//排序 { void swap(int *j1,int *j2); if (*q1>*q2)//不可使用if……else if……else if……只执行一个语句 { /* code */ swap(q1,q2); } if (*q1>*q3) { /* code */ swap(q1,q3); } if (*q2>*q3) { /* code */ swap(q2,q3); } } void swap(int *j1,int *j2)//交换值 { int temp; temp=*j1; *j1=*j2; *j2=temp; }
20277
#include <stdio.h> int main() { void exchange(int *p, int *q); int a[10], n = 10, *p; for (int i = 0; i < 10; i++) { /* code */ scanf("%d", &a[i]); } p = a; for (int i = 0; i < n / 2; i++) { exchange((p+i), (p+9-i)); } for (int i = 0; i < 10; i++) { printf("%d ", a[i]); } return 0; } void exchange(int *p, int *q) //排序 { /* code */ int temp; temp = *p; *p=*q; *q=temp; }
20308
#include <stdio.h> //声明一个名字为Student的数据类型 // your code #define M 5 int main() { //your code begin struct Student { int num; char *name; float score; } stu[M] = {{10101, "Zhang", 78}, {10103, "Wang", 98.5}, {10106, "Li", 86}, {10108, "Ling", 73.5}, {10110, "Fun", 100}}; for (int j = 0; j < M; j++) { for (int i = 0; i < M - j; i++) { if (stu[i].score < stu[i + 1].score) { int num1; char *name1; float score1; num1 = stu[i].num; stu[i].num = stu[i + 1].num; stu[i + 1].num = num1; name1 = stu[i].name; stu[i].name = stu[i + 1].name; stu[i + 1].name = name1; score1 = stu[i].score; stu[i].score = stu[i + 1].score; stu[i + 1].score = score1; } } } for (int i = 0; i < M; i++) { /* code */ printf("%d %s %.2f\n", stu[i].num, stu[i].name, stu[i].score); } //your code end return 0; }
#include <stdio.h> //声明一个名字为Student的数据类型 // your code #define M 5 int main() { //your code begin struct Student { int num; char *name; float score; } stu[M] = {{10101, "Zhang", 78}, {10103, "Wang", 98.5}, {10106, "Li", 86}, {10108, "Ling", 73.5}, {10110, "Fun", 100}}; for (int j = 0; j < M; j++) { for (int i = 0; i < M - j; i++) { if (stu[i].score < stu[i + 1].score) { struct Student temp; temp=stu[i]; stu[i]=stu[i+1]; stu[i+1]=temp; } } } for (int i = 0; i < M; i++) { /* code */ printf("%d %s %.2f\n", stu[i].num, stu[i].name, stu[i].score); } //your code end return 0; }
20309
#include <stdio.h> int main() { struct student { int num; char* name; char sex; int age; }stu[]={{10101,"Li Lin",'M',18},{10102,"Zhang Fun",'M',19},{10104,"Wang Min",'F',20}}; printf("No.Name sex age "); for (int i = 0; i < 3; i++) { printf("%d %s %c %d",stu[i].num,stu[i].name,stu[i].sex,stu[i].age); } }
#include <stdio.h> struct student { int num; char name[20]; char sex; int age; }; struct student stu[3]= {{10101,"Li Lin",'M',18},{10102,"Zhang Fun",'M',19},{10104,"Wang Min",'F',20}}; int main() { struct student *p; printf("No. Name sex age\n"); for (p=stu; p<stu+3;p++) printf("%d %s %c %d\n",p->num, p->name, p->sex, p->age); return 0; }
问题
无法输出
#include <stdio.h> struct student { int num; char* name; char sex; char* address; }stu; int main() { printf("xuehao1:"); scanf("%d%s%c%s",&stu.num,&stu.name,&stu.sex,&stu.address); printf("%d %s %c %s",stu.num,stu.name,stu.sex,stu.address); return 0; }
能正确输出,两次回车键
#include <stdio.h> struct student { int num; char name[20]; char sex; }stu; int main() { printf("开始输入:"); scanf("%d",&stu.num); gets(stu.name); stu.sex=getchar(); printf("输出%d %s %c",stu.num,stu.name,stu.sex); return 0; }
