题目描述
We have a grid with H rows and W columns. The square at the i-th row and the j-th column will be called Square (i,j).
The integers from 1 through H×W are written throughout the grid, and the integer written in Square (i,j) is Ai,j.
You, a magical girl, can teleport a piece placed on Square (i,j) to Square (x,y) by consuming |x−i|+|y−j| magic points.
You now have to take Q practical tests of your ability as a magical girl.
The i-th test will be conducted as follows:
Initially, a piece is placed on the square where the integer Li is written.
Let x be the integer written in the square occupied by the piece. Repeatedly move the piece to the square where the integer x+D is written, as long as x is not Ri. The test ends when x=Ri.
Here, it is guaranteed that Ri−Li is a multiple of D.
For each test, find the sum of magic points consumed during that test.
Constraints
1≤H,W≤300
1≤D≤H×W
1≤Ai,j≤H×W
Ai,j≠Ax,y((i,j)≠(x,y))
1≤Q≤105
1≤Li≤Ri≤H×W
(Ri−Li) is a multiple of D.
输入
Input is given from Standard Input in the following format:
H W D A1,1 A1,2 … A1,W : AH,1 AH,2 … AH,W Q L1 R1 : LQ RQ
输出
For each test, print the sum of magic points consumed during that test.
Output should be in the order the tests are conducted.
样例输入
3 3 2 1 4 3 2 5 7 8 9 6 1 4 8
样例输出
5
提示
4 is written in Square (1,2).
6 is written in Square (3,3).
8 is written in Square (3,1).
Thus, the sum of magic points consumed during the first test is (|3−1|+|3−2|)+(|3−3|+|1−3|)=5.
刚开始疯狂T了两次，原来是这个题目卡cout
#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector,fast-math") #pragma GCC optimize("Ofast") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #pragma comment(linker, "/stack:200000000") #pragma GCC optimize (2) #pragma G++ optimize (2) #include <bits/stdc++.h> #include <algorithm> #include <map> #include <queue> #include <set> #include <stack> #include <string> #include <vector> using namespace std; #define wuyt main typedef long long ll; #define HEAP(...) priority_queue<__VA_ARGS__ > #define heap(...) priority_queue<__VA_ARGS__,vector<__VA_ARGS__ >,greater<__VA_ARGS__ > > template<class T> inline T min(T &x,const T &y){return x>y?y:x;} template<class T> inline T max(T &x,const T &y){return x<y?y:x;} ///#define getchar()(p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 1 << 21, stdin), p1 == p2) ? EOF : *p1++) ///char buf[(1 << 21) + 1], *p1 = buf, *p2 = buf; ll read(){ll c = getchar(),Nig = 1,x = 0;while(!isdigit(c) && c!='-')c = getchar(); if(c == '-')Nig = -1,c = getchar(); while(isdigit(c))x = ((x<<1) + (x<<3)) + (c^'0'),c = getchar(); return Nig*x;} #define read read() const ll inf = 1e15; const int maxn = 2e5 + 7; const int mod = 1e9 + 7; #define start int wuyt() #define end return 0 int cnt; string s; int num[maxn]; int x[maxn],y[maxn]; start{ int h=read,w=read,d=read; for(int i=0;i<h;i++){ for(int j=0;j<w;j++){ int temp=read; x[temp]=i; y[temp]=j; } } for(int i=d+1;i<=h*w;i++) num[i]=num[i-d]+abs(x[i]-x[i-d])+abs(y[i]-y[i-d]); int q=read; for(int i=1;i<=q;i++){ int l=read,r=read; printf("%d\n",num[r]-num[l]); } end; } /************************************************************** Language: C++ Result: 正确 Time:41 ms Memory:4368 kb ****************************************************************/
