In the C++ STL, the vector size() function return size_t, which is unsigned int, not int. So imagine this, define an empty vector<int> v, and v.size() should be 0, and you have a for loop, and has an end condition is v.size() - 1, which is 4294967295 actually, not -1. This might cause problem when i = 0, which can enter the for loop, but actually was supposed not entering it.
vector<int> v; cout << v.size() << endl; // 0 cout << v.size() - 1 << endl; // 4294967295 cout << v.size() - 2 << endl; // 4294967294 cout << v.size() << endl; // 0 cout << int(v.size() - 1) << endl; // -1 cout << int(v.size() - 2) << endl; // -2
本文转自博客园Grandyang的博客，原文链接：返回无符号整型数v.size() return size_t not int ，如需转载请自行联系原博主。
