Description
A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59).
Each LED represents a zero or one, with the least significant bit on the right.
For example, the above binary watch reads "3:25".
Given a non-negative integer n which represents the number of LEDs that are currently on, return all possible times the watch could represent.
Example:
Input: n = 1 Return: ["1:00", "2:00", "4:00", "8:00", "0:01", "0:02", "0:04", "0:08", "0:16", "0:32"]
Note:
The order of output does not matter.
The hour must not contain a leading zero, for example "01:00" is not valid, it should be "1:00".
The minute must be consist of two digits and may contain a leading zero, for example "10:2" is not valid, it should be "10:02".
描述
二进制手表顶部有 4 个 LED 代表小时（0-11），底部的 6 个 LED 代表分钟（0-59）。
每个 LED 代表一个 0 或 1，最低位在右侧。
例如，上面的二进制手表读取 “3:25”。
给定一个非负整数 n 代表当前 LED 亮着的数量，返回所有可能的时间。
案例:
输入: n = 1 返回: ["1:00", "2:00", "4:00", "8:00", "0:01", "0:02", "0:04", "0:08", "0:16", "0:32"]
注意事项:
输出的顺序没有要求。
小时不会以零开头，比如 “01:00” 是不允许的，应为 “1:00”。
分钟必须由两位数组成，可能会以零开头，比如 “10:2” 是无效的，应为 “10:02”。
来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/binary-watch
著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。
思路
- 对每个位置编号 （范围是 [0,9]，一共 10 个位置），形成键值对；键位编号，值表盘对应的时间。
- 其中，对分钟用 range(0,6) 进行编号；小时用 range(6,10) 进行编号；
- 对于输入 num，使用 Python 的 combinations 模块，从 list(range(10)) 中随机选取 num 个数字；然后以这些数字为键，拿到对应的小时和分钟数，构成当前时间；对于不符合要求的时间直接丢弃；
# -*- coding: utf-8 -*- # @Author: 何睿 # @Create Date: 2019-09-03 22:35:31 # @Last Modified by: 何睿 # @Last Modified time: 2019-09-04 08:59:55 from typing import List from itertools import combinations class Solution: def readBinaryWatch(self, num: int) -> List[str]: minutes = {i: 2**i for i in range(6)} hours = {i: 2**(i - 6) for i in range(6, 10)} times = map(lambda x: self.__transfer(x, minutes, hours), combinations(list(range(10)), num)) return filter(lambda x: x is not None, times) def __transfer(self, com, minutes, hours): minute = sum(map(lambda x: minutes.get(x, 0), com)) hour = sum(map(lambda x: hours.get(x, 0), com)) return "{}:{:02d}".format(hour, minute) if hour <= 11 and minute <= 59 else None
源代码文件在 这里 。
