C语言实现扫雷

扫雷游戏，相信大家都玩过，今天练习用C语言实现扫雷。先介绍一下规则，因为是C语言实现，所以每次要输入想排查的雷的坐标，若该坐标为雷则失败；若该坐标周边八个坐标中有雷，则显示雷个数，若无雷则继续向周边延伸排查，一直到某坐标周边8个坐标有雷为止
先看代码，再看思路及我觉得其中比较难实现的部分
本文中用到的一个工程中包含多个文件的方法，它们之间的关系及对应思路，在这个文章中有介绍过，大家可以去看http://t.csdn.cn/qnOxE
一、文件及其对应代码
1.test.c
#include"game.h"
void menu()
{
  printf("*****************************\n");
  printf("*********  1.play   *********\n");
  printf("*********  0.exit   *********\n");
  printf("*****************************\n");
}
void game()
{
  char mine[ROWS][COLS] = {0};
  char show[ROWS][COLS] = {0};
  //初始化棋盘
  InitBoard(mine, ROWS, COLS,'0');
  InitBoard(show, ROWS, COLS,'*');
  //打印棋盘
  //DisplayBoard(mine, ROW, COL);
  DisplayBoard(show, ROW, COL);
  //布置雷
  SetMine(mine, ROW, COL);
   //DisplayBoard(mine, ROW, COL);
  //排查雷
  FindMine(mine, show, ROW, COL);
}
int main()
{
  int input = 0;
  srand((unsigned int)time(NULL));
  //扫雷游戏
  do
  {
    menu();
    scanf("%d", &input);
    switch (input)
    {
    case 1:
      game();
      break;
    case 0:
      printf("退出游戏\n");
      break;
    default:
      printf("输入错误，请重新选择:\n");
      break;
    }
  } while (input);
  return 0;
}

#include"game.h"
//初始化棋盘,初始11*11的
InitBoard(char Board[ROWS][COLS], int rows, int cols,char ret)
{
  int i = 0;
  for (i = 0; i < rows; i++)
  {
    int j = 0;
    for (j = 0; j < cols; j++)
    {
      Board[i][j] = ret;
    }
  }
}
//打印棋盘
DisplayBoard(char Board[ROWS][COLS], int row, int col)
{
  int i = 0;
  printf("----------扫雷游戏---------\n");
  for (i = 0; i <= col; i++)
  {
    printf("%d  ", i);
  }
  printf("\n");
  for (i = 1; i <= row; i++)
  {
    int j = 0;
    printf("%d  ",i);
    for (j = 1; j <=col; j++)
    {
      printf("%c  ", Board[i][j]);
    }
    printf("\n");
  }
}
//布置雷
SetMine(char mine[ROWS][COLS], int row, int col)
{
  int count1 = 1;
  while (count1 <= count)
  {
    int x = rand() % row + 1;
    int y = rand() % col + 1;
    if (mine[x][y] == '0')
    {
      mine[x][y] = '1';
      count1++;
    }
  }
}
//排查雷
void menu2()
{
  printf("1.排查雷\n");
  printf("2.标记雷\n");
}
FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
  int blank = row * col - count;
  while (blank > 0)
  {
    printf("请输入你要排查的坐标:");
    int x = 0;
    int y = 0;
    scanf("%d %d", &x, &y);
    if (x >= 1 && x <= row && y >= 1 && y <= col)
    {
      if (mine[x][y] == '1')
      {
        printf("抱歉，你被炸死了,游戏结束\n");
        printf("雷的具体信息为:\n");
        DisplayBoard(mine, ROW, COL);
        break;
      }
      else
      {
        Change(mine, show, ROW, COL, x, y);
        DisplayBoard(show, ROW, COL);
        blank--;
      }
    }
    else
      printf("输入错误，请重新输入:\n");
  }
}
//判断周围有几个雷
int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
  return (mine[x - 1][y - 1] + mine[x - 1][y] + mine[x - 1][y + 1] + mine[x][y - 1] + mine[x][y + 1] + mine[x + 1][y - 1] + mine[x + 1][y] + mine[x + 1][y + 1] - 8 * '0');
}
//对周围延伸继续向外判断
void Change(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col,int x, int y)
{
  int count_ = GetMineCount(mine, x, y);
  if (count_ == 0)
  {
    //遍历周围8个坐标
    show[x][y] = ' ';
    int i = 0;
    for (i = x - 1; i <= x + 1; i++)
    {
      int j = 0;
      for (j = y - 1; j <= y + 1; j++)
      {
        if(show[i][j]=='*')
          Change(mine, show, ROW, COL, i,j);
      }
    }
  }
  else
    show[x][y] = count_ + '0';
}

#pragma once
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#define count 10
InitBoard(char Board[ROWS][COLS], int rows, int cols,char ret);
DisplayBoard(char Board[ROWS][COLS], int row, int col);
SetMine(char mine[ROWS][COLS], int row, int col);
FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);
int GetMineCount(char mine[ROWS][COLS], int row, int col);
//int GetMineCount2(char mine[ROWS][COLS], char show[ROWS][COLS], int x, int y,int* blank);
void Change(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col, int x, int y);