realloc：pointer being realloc'd was not allocated

在做一个leetcode的题，遇到了一个奇怪的问题，调用realloc为array扩容，报错

malloc: error for object 0x7f7fc0404bf0: pointer being realloc'd was not allocated
在下面的代码中，第一次realloc的时候是ok的，第二次调用到realloc的时候就会报错了

请问如何修改可以解决，以及为什么

#include "stdio.h"
#include "stdlib.h"
#include "string.h"

void generate(int left, int right, int currentLen, char* str, char** result, int* resultCount, int* resultCapacity) {
    if (right < left) {
        return;
    }
    if (left == 0 && right == 0) {
        char* temp = malloc(sizeof(char) * (currentLen + 1));
        temp = strcpy(temp, str);
        result[*resultCount] = temp;
        (*resultCount)++;
    }
    if (*resultCount >= *resultCapacity) {
        *resultCapacity = (*resultCapacity) * 2;
        char** temp = realloc(result, sizeof(char*) * (*resultCapacity));
        result = temp;
    }
    if (left > 0)  {
        str[currentLen] = '(';
        str[currentLen + 1] = '\0';
        generate(left - 1, right, currentLen + 1, str, result, resultCount, resultCapacity);
    }
    if (right > 0) {
        str[currentLen] = ')';
        str[currentLen + 1] = '\0';
        generate(left, right - 1, currentLen + 1, str, result, resultCount, resultCapacity);
    }
}

char** generateParenthesis(int n, int* returnSize) {
    if (n < 1) {
        return NULL;
    }
    int* resultCount = malloc(sizeof(int));
    int* resultCapacity = malloc(sizeof(int));
    (*resultCount) = 0;
    (*resultCapacity) = n;
    char** result = malloc(sizeof(char*) * (*resultCapacity));
    char* str = malloc(sizeof(char) * (n * 2 + 1));
    generate(n, n, 0, str, result, resultCount, resultCapacity);
    *returnSize = *resultCount;
    return result;
}

int main(int argc, char const *argv[]) {
    int* returnSize = malloc(sizeof(int));
    char** result = generateParenthesis(5, returnSize);
    for (int i = 0; i < *returnSize; ++i) {
        printf("%s\n", result[i]);
    }
    return 0;
}