JSON.parseObject有重大问题

问题描述

getStringCoder 67 line unsafe get String.coder error

环境信息

版本信息：[e.g.：Fastjson2 2.0.7] 重现步骤

public static byte getStringCoder(String str) {
    // GraalVM not support
    // Android not support
    if (str == null) {
        throw new NullPointerException();
    }
    if (JDKUtils.JVM_VERSION == 8) {
        return 1;
    }
    if (STRING_CODER_OFFSET == 0) {
        try {
            Field fieldCode = String.class.getDeclaredField("coder");
            STRING_CODER_OFFSET = UNSAFE.objectFieldOffset(fieldCode);
        } catch (Exception e) {
            throw new JSONException("unsafe get String.coder error", e);
        }
    }
    return UNSAFE.getByte(str, STRING_CODER_OFFSET);
}

fun getJsonFromAssetPath(context: Context, path: String): String? { var inputStream: InputStream? = null try { inputStream = context.assets.open(path) return JSON.parseObject(inputStream, UTF_8, String::class.java) } catch (e: Exception) { CommonLogUtils.e( Tag.TAG, "getJsonFromAsset is error " + e.message ) } finally { try { inputStream?.close() } catch (e: IOException) { CommonLogUtils.e( Tag.TAG, "getJsonFromAsset is error " + e.message ) } } return null }

期待的正确结果

JSON.parseObject有重大问题，解析unsafe get String.coder error，希望修正

原提问者GitHub用户wangshuai7777