6=1＋2＋3.编程找出1000以内的所有完数。

from functools import reduce

def is_perfect_number2(num):
    if num == reduce(lambda x, y: x + y, [x for x in range(1, num) if not num % x]):
        return True
    else:
        return False


if __name__ == '__main__':
    for i in range(2, 1001):
        if is_perfect_number2(i):
            print(i)

#!/usr/bin/python
# -*- coding: UTF-8 -*-

from sys import stdout
for j in range(2,1001):
    k = []
    n = -1
    s = j
    for i in range(1,j):
            if j % i == 0:
                n += 1
                s -= i
                k.append(i)
   
    if s == 0:
        print j
        for i in range(n):
            stdout.write(str(k[i]))
            stdout.write(' ')
        print k[n]

以上实例输出结果为：

6
1 2 3
28
1 2 4 7 14
496
1 2 4 8 16 31 62 124 248