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如何清除多个列表或字典?

我有大量的列表和字典,它们需要在每次迭代中清除。我试图写一个函数的GlobalClear,其中有一个列表包含着要清除的列表或字典名称。

Result1={"d11":"1","d12":"2"}

Result2 =["l11","l22"]

def length(name):

print(str(name) + "  having length is : "+ str(len(name)))

def GlobalClear():

overallList = ["Result1", "Result2"]

for key in overallList:

    list(key).clear()

    length(list(key))

print("Prev Length")

length(Result1)

length(Result2)

GlobalClear()

print("Final Length")

length(Result1)

length(Result2)

输出: Prev Length

{'d11': '1', 'd12': '2'} having length is : 2

['l11', 'l22'] having length is : 2

['R', 'e', 's', 'u', 'l', 't', '1'] having length is : 7

['R', 'e', 's', 'u', 'l', 't', '2'] having length is : 7

Final Length

{'d11': '1', 'd12': '2'} having length is : 2

['l11', 'l22'] having length is : 2

预期输出: Prev Length

{'d11': '1', 'd12': '2'} having length is : 2

['l11', 'l22'] having length is : 2

Final Length

{'d11': '1', 'd12': '2'} having length is : 0

['l11', 'l22'] having length is : 0

有没有解决这个问题的好办法?谢谢!

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游客6qcs5bpxssri2 2019-10-11 16:32:41 2641 0
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  • 您可以存储对列表本身的引用,并对其调用clear(),而不是存储列表的名称。

    Result1={"d11":"1","d12":"2"}

    Result2 =["l11","l22"]

    def length(name):

    print(str(name) + "  having length is : "+ str(len(name)))
    

    def GlobalClear():

    overallList = [Result1, Result2]
    
    for key in overallList:
    
        key.clear()
    

    print("Prev Length")

    length(Result1)

    length(Result2)

    GlobalClear()

    print("Final Length")

    length(Result1)

    length(Result2)

    2019-10-11 16:33:58
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