1、题目
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:
1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.
You need to output the length L and the width W of the web page you designed in sequence.
Example:
Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Note:
The given area won't exceed 10,000,000 and is a positive integer
The web page's width and length you designed must be positive integers.
2、代码实现
public class Solution {
public int[] constructRectangle(int area) {
if (area < 0)
return null;
int[] a = new int[2];
if (area == 0) {
a[0] = 0;
a[1] = 0;
return a;
}
int mid = (int)Math.sqrt(area);
if (mid == 1) {
a[0] = area;
a[1] = 1;
return a;
}
int l1 = 0, l2 = 0;
int w1 = 0, w2 = 0;
int sub1 = 0, sub2 = 0;
//area是平方数的时候
if (mid * mid == area) {
a[0] = mid;
a[1] = mid;
return a;
} else {
for (int i = mid; i > 0; --i) {
if (area % i == 0) {
l1 = area / i;
w1 = i;
sub1 = mid - i;
break;
}
}
for (int j = mid; j <= area; ++j) {
if (area % j == 0) {
w2 = area / j;
l2 = j;
sub2 = j - mid;
}
}
}
if (sub1 <= sub2) {
a[0] = l1;
a[1] = w1;
} else {
a[0] = l2;
a[1] = w2;
}
return a;
}
}
