动态规划 HDOJ2602-Bone Collector-01背包

简介: Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 40794    Accepted Submission(s): 16961 Problem Description Many year

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 40794    Accepted Submission(s): 16961

Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?



Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 
Output
One integer per line representing the maximum of the total value (this number will be less than 2 31).

Sample Input
 
 
1 5 10 1 2 3 4 5 5 4 3 2 1

Sample Output
 
 
14

1.题目大意

有个人叫“骨头收集者”,他有一个包,最多能放下重量为xx 的物品。不同骨头有不同价值和重量,求能收集骨头的最大价值。

2.输入

T
N W
V1 V2 ... Vn
W1 W2 ... Wn
------
T:case个数。
N:N个骨头。
W:背包容量。
Vi:第i个骨头的价值。
Wi:第i个骨头的重量。

3.输出

能够收集的骨头的最大价值。

4.分析

标标准准的01背包。

5.代码

微笑代码1:二维dp[][]
微笑代码2:一维dp[]




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