hdu 1102 Constructing Roads

简介:
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <time.h>
using namespace std;
struct data
{
    int u,v,w;
}e[105*105];
int bin[100+5],use[100+5][100+5],mp[100+5][100+5];
bool cmp(data a,data b)
{
    return a.w<b.w;
}

int Find(int x)
{
    int s;
    for(s=x;bin[s]>=0;s=bin[s]);

    while(s!=x)
    {
        int t=bin[x];
        bin[x]=s;
        x=t;
    }
    return s;
}

void Union(int x1,int x2)
{
    int f1=Find(x1),f2=Find(x2);
    int temp=bin[f1]+bin[f2];
    if(bin[f1]>bin[f2])
    {
        bin[f1]=f2;
        bin[f2]=temp;
    }
    else
    {
        bin[f2]=f1;
        bin[f1]=temp;
    }
}

int main()
{
    int n,i,j,u,v,w,m,k,a,b;
    while(~scanf("%d",&n))
    {
        for(i=0;i<=n;i++) bin[i]=-1;
        for(i=1;i<=n;i++)
        {
            for(j=1;j<=n;j++)
            {
                scanf("%d",&mp[i][j]);
            }
        }

        scanf("%d",&k);
        memset(use,0,sizeof(use));
        for(i=0;i<k;i++)
        {
            scanf("%d%d",&a,&b);
            if(Find(a)!=Find(b)) Union(a,b);
            use[a][b]=use[b][a]=1;
        }
        m=0;
        for(i=1;i<=n;i++)
        {
            use[i][i]=1;
            for(j=1;j<=n;j++)
            {
                if(use[i][j]==0&&use[j][i]==0)
                {
                    e[m].u=i;
                    e[m].v=j;
                    e[m].w=mp[i][j];
                    use[i][j]=use[j][i]=1;
                    m++;
                }
            }
        }
        sort(e,e+m,cmp);
        int sum=0;
        for(i=0;i<m;i++)
        {
            u=e[i].u;
            v=e[i].v;
            if(Find(u)!=Find(v))
            {
                Union(u,v);
                sum+=e[i].w;
            }
        }
        printf("%d\n",sum);
    }
    return 0;
}





本文转自mfrbuaa博客园博客,原文链接:http://www.cnblogs.com/mfrbuaa/p/5276426.html,如需转载请自行联系原作者
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