Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.
Notice
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
Example
Given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].
LeetCode上的原题，请参见我之前的博客Move Zeroes。
解法一：
class Solution { public: /** * @param nums an integer array * @return nothing, do this in-place */ void moveZeroes(vector<int>& nums) { for (int i = 0, j = 0; i < nums.size(); ++i) { if (nums[i]) { swap(nums[i], nums[j++]); } } } };
解法二：
class Solution { public: /** * @param nums an integer array * @return nothing, do this in-place */ void moveZeroes(vector<int>& nums) { int left = 0, right = 0; while (right < nums.size()) { if (nums[right]) { swap(nums[left++], nums[right]); } ++right; } } };
本文转自博客园Grandyang的博客，原文链接：移动零[LintCode] Move Zeroes ，如需转载请自行联系原博主。
