Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
注意是不是头结点就ok了。
C++实现代码:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* removeElements(ListNode* head, int val) {
if(head==NULL)
return NULL;
ListNode *p=head;
ListNode *pre=head;
while(p)
{
if(p->val==val)
{
if(p==head)
{
head=p->next;
p->next=NULL;
delete p;
pre=head;
p=head;
}
else
{
pre->next=p->next;
p->next=NULL;
delete p;
p=pre->next;
}
}
else
{
pre=p;
p=p->next;
}
}
return head;
}
};