Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
注意是不是头结点就ok了。
C++实现代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* removeElements(ListNode* head, int val) { if(head==NULL) return NULL; ListNode *p=head; ListNode *pre=head; while(p) { if(p->val==val) { if(p==head) { head=p->next; p->next=NULL; delete p; pre=head; p=head; } else { pre->next=p->next; p->next=NULL; delete p; p=pre->next; } } else { pre=p; p=p->next; } } return head; } };