Python 微分法计算定积分，以及用lambda函数作函数的形参

from math import sin
from math import log
from math import exp
from math import pi
from math import e
N=1000000
def interalSin(a,b):
    '''sin(x)在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*sin(a+i*d+d/2)
    return r
def interalLn(a,b):
    '''ln(x)在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*log(a+i*d+d/2)
    return r
def interalAbs(a,b):
    '''ln(x)在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*abs(a+i*d+d/2)
    return r
def interalExp(a,b):
    '''e^x在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*exp(a+i*d+d/2)
    return r
print(interalSin(0,pi/2))
print(interalLn(1,e))
print(interalAbs(-1,1))
print(interalExp(-1,1),end='\n\n')
print('e-1/e=')
print(e-1/e)
#执行结果：
'''
1.0000000000000981
1.0000000000000977
1.0000000000000002
2.3504023872872146
e-1/e=
2.3504023872876028
>>> 
'''

from math import sin
from math import log
from math import exp
from math import pi
from math import e
N=1000000
def Sinx(x):
    return sin(x)
def Ln_x(x):
    return log(x)
def Absx(x):
    return abs(x)
def Expx(x):
    return exp(x)
def Interal(func,a,b):
    '''func(x)在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*func(a+i*d+d/2)
    return r
print(Interal(Sinx,0,pi/2))
print(Interal(Ln_x,1,e))
print(Interal(Absx,-1,1))
print(Interal(Expx,-1,1))

from math import sin
from math import log
from math import exp
from math import pi
from math import e
N=1000000
def Interal(func,a,b):
    '''func(x)在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*func(a+i*d+d/2)
    return r
print(Interal(sin,0,pi/2))
print(Interal(log,1,e))
print(Interal(abs,-1,1))
print(Interal(exp,-1,1))

from math import pi
from math import sin
from math import cos
from math import log
from math import sqrt
N=1000000
fx=lambda x:sqrt(1-sin(2*x))
gx=lambda x:sin(x)/(1+sin(x)+cos(x))
def Interal(func,a,b):
    '''func(x)在区间[a,b]上的定积分'''
    d=(b-a)/N
    r=0
    for i in range(N):
        r+=d*func(a+i*d+d/2)
    return r
print(Interal(fx,0,pi/2))
print(2*sqrt(2)-2) #对比答案
print()
print(Interal(gx,0,pi/2))
print((pi/2-log(2))/2) #对比答案
'''
0.8284271247463156
0.8284271247461903
0.43882457311750606
0.43882457311747564
>>>
'''

def plus(*args):
    tmp=0
    for i in args:
        tmp+=i
    return tmp
def mul_p(fn,x,*args):
    return x*fn(*args)
print(plus(1,2,3,4,5,6,7,8,9,10))
print(mul_p(plus,10,1,2,3,4,5,6,7,8,9,10))
#执行结果：
'''
55
550
>>> 
'''