python 钉钉文件上传

from urllib3 import encode_multipart_formdata
import requests
headers={}
data={}
url = 'https://oapi.dingtalk.com/media/upload?access_token=' + access_token + '&type=file'
def post_files(url,headers,data,filename,filepath):

"""
    :param files: (optional) Dictionary of ``'name': file-like-objects`` (or ``{'name': file-tuple}``) for multipart encoding upload.
    ``file-tuple`` can be a 2-tuple ``('filename', fileobj)``, 3-tuple ``('filename', fileobj, 'content_type')``
    or a 4-tuple ``('filename', fileobj, 'content_type', custom_headers)``, where ``'content-type'`` is a string
    defining the content type of the given file and ``custom_headers`` a dict-like object containing additional headers
    to add for the file.
"""
data['media']= ('test.py', open(r'C:\Users\Administrator\Desktop\test.py', 'rb').read())
encode_data = encode_multipart_formdata(data)
data = encode_data[0]
headers['Content-Type'] = encode_data[1]
r = requests.post(url, headers=headers, data=data)
print(json.loads(r.text)["media_id"])

from urllib3 import encode_multipart_formdata
import requests
headers={}
data={}
url = 'https://oapi.dingtalk.com/media/upload?access_token=' + access_token + '&type=file'
def post_files(url,headers,data,filename,filepath):

data['media']= ('test.py', open(r'C:\Users\Administrator\Desktop\test.py', 'rb').read())
encode_data = encode_multipart_formdata(data)
data = encode_data[0]
headers['Content-Type'] = encode_data[1]
r = requests.post(url, headers=headers, data=data)
print(json.loads(r.text)["media_id"])

for filename in file_dict.keys():
  files[filename] = open(file_dict[filename], mode='rb')
r = requests.post(url, data=data,files=files)

如果你说的是钉钉这个接口的话：https://open-doc.dingtalk.com/docs/doc.htm?spm=a219a.7629140.0.0.JknMf3&treeId=172&articleId=104971&docType=1

应该是用这种方式来上传，接口文档描述得确实不是很清晰，给的是java的代码示例，对于mutipart格式的接口来说，这个接口协议就是耍榴芒。

建议楼主修改下问题描述，我也没看明白啊

您具体的需求是什么呢？如果单纯是后缀问题，您可以在您自行的业务系统中处理的