开发者社区> 问答> 正文

jquery1.5 find方法在ie,火狐下遇到的问题??

发现find在火狐下找不到多级的后代元素,只能找到后一代元素。在ie下能找到多级后代元素。大家知道为什么吗?请指点一下。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript" language="javascript" src="/js/jquery/jquery1.5.js"></script>
<title>inuptEvaluation Test</title>
</head>
<body>
    
    <table cellpadding="0" cellspacing="0" border="0" width="100%">    
  <tbody id="rootmenu">
  <form  method="get" id="FirstForm" name="searchForm">
             <tr>
              <td>用户Id:<input class="textinput" type="text" id="siteId" name="siteId" reg='{"isnull":"no","length":"30","func":"num"}'/></td>
                    <td>相册Id:<input class="textinput" type="text" id="albumId" name="albumId"  reg='{"isnull":"no","length":"30","func":"num"}'/></td>
                    <td>照片Id:<input class="textinput" type="text" id="photoId" name="photoId"  reg='{"length":"30","func":"num"}'/></td>
                    <td></td>
                </tr>
            </form>
  </tbody>           
   </table>
   
      <br/>
         
      <table cellpadding="0" cellspacing="0" border="0" width="100%">
          <tr><td>
            <form method="get" id="SecondForm" name="searchForm">
  用户Id:<input class="textinput" type="text" id="siteId" name="siteId" reg='{"isnull":"no","length":"30","func":"num"}'/>
                    相册Id:<input class="textinput" type="text" id="albumId" name="albumId"  reg='{"isnull":"no","length":"30","func":"num"}'/>照片Id:<input class="textinput" type="text" id="photoId" name="photoId"  reg='{"length":"30","func":"num"}'/>
             </form>
             </td>
            </tr>
       </table>
</div> 
<script>
$(function(){
 alert("FirstForm** "+$("#FirstForm").find(":input[reg]").size()); --ie下3 ,火狐下为0
 alert("SecondForm** "+$("#SecondForm").find(":input[reg]").size());--ie下3 ,火狐下为0
 
 });
</script>
</body>
</html>

展开
收起
a123456678 2016-07-06 10:52:43 2432 0
1 条回答
写回答
取消 提交回答
  • <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <script type="text/javascript" language="javascript" src="/js/jquery/jquery1.5.js"></script>
    <title>inuptEvaluation Test</title>
    </head>
    <body>
        
    <form  method="get" id="FirstForm" name="searchForm">    
    <table cellpadding="0" cellspacing="0" border="0" width="100%">    
      <tbody id="rootmenu">
       
                 <tr>
                  <td>用户Id:<input class="textinput" type="text" id="siteId" name="siteId" reg='{"isnull":"no","length":"30","func":"num"}'/></td>
                        <td>相册Id:<input class="textinput" type="text" id="albumId" name="albumId"  reg='{"isnull":"no","length":"30","func":"num"}'/></td>
                        <td>照片Id:<input class="textinput" type="text" id="photoId" name="photoId"  reg='{"length":"30","func":"num"}'/></td>
                        <td></td>
                    </tr>
                  </tbody>           
       </table>
      </form>
     
          <br/>
             <form method="get" id="SecondForm" name="searchForm">
          <table cellpadding="0" cellspacing="0" border="0" width="100%">
              <tr><td>
                
      用户Id:<input class="textinput" type="text" id="siteId" name="siteId" reg='{"isnull":"no","length":"30","func":"num"}'/>
                        相册Id:<input class="textinput" type="text" id="albumId" name="albumId"  reg='{"isnull":"no","length":"30","func":"num"}'/>照片Id:<input class="textinput" type="text" id="photoId" name="photoId"  reg='{"length":"30","func":"num"}'/>
                  
                 </td>
                </tr>
           </table>
    </form>
    </div> 
    <script>
    $(function(){
     alert("FirstForm** "+$("#FirstForm").find(":input[reg]").size()); 
     alert("SecondForm** "+$("#SecondForm").find(":input[reg]").size());
     
     });
    </script>
    </body>
    </html>
    2019-07-17 19:51:57
    赞同 展开评论 打赏
问答分类:
问答标签:
问答地址:
问答排行榜
最热
最新

相关课程

更多

相关电子书

更多
Delivering Javascript to World 立即下载
低代码开发师(初级)实战教程 立即下载
阿里巴巴DevOps 最佳实践手册 立即下载