用js或jquery怎么根据不同的选择打印出不同的结果!

如果有N个问题，那么构建一个N维数组，通过查表计算arrselect_1[select_3][]...[select_n]来获得结果。
比如你的题目有2个问题，那么就构建一个二维数组，预先存储一个表。

赋值阶段可以区分一下数组是不是足够酥松

如果酥松的话就把有值的地方赋好就行了：

var arr = Array(2);
arr[0] = Array(10) ;
arr[1] = Array(10) ;

arr[0][0] = "123"
arr[3][4] = "123123"
arr[5][10] = "21312"

function showAnswerForSelects(){
    return arr[arguments[0]][arguments[1]] ;
}
showAnswerForSelects(3,4)
-> "123123"
showAnswerForSelects(7,5)
-> undefined
或者数据比较酥松，还可以构建一个switch逻辑，像这样：

function showAnswerForSelects(){
    var str = arguments[0] + "-" + arguments[1] ;
    switch(str) {
        case "0-1": return "123" ;
        case "3-4": return "123123" ;
        case "5-10": return "21312" ;
        default: return null;
    }
}

调用还是一样的方式。

如果比较密，那么就用字面量的方式直接赋值吧：

var arr = [
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"] ,
    ["123123","12312","123123"..."234134"]
];

function showAnswerForSelects(){
    return arr[arguments[0]][arguments[1]] ;
}

嫌不好索引还可以用@kikong的对象字面量的方式来做。