java List合并相同的项的问题？

提供一种程序实现的思路 具体还的你自己修改·

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
 
 
public class Test {
 
    /**
     * @param args
     */
    public static void main(String[] args) {
        Map<String,String[]> map=new HashMap<String,String[]>();//存放叠加的数据
        List<String[]> list=new ArrayList<String[]>();//数据list
        list.add(new String[]{"金点子","封面","彩板","5","1","4"});
        list.add(new String[]{"金点子","封面","彩板","5","1","4"});
        list.add(new String[]{"金点子","封面","彩板","5","1","4"});
        list.add(new String[]{"金点子","封面","彩板","5","1","4"});
        list.add(new String[]{"金点子","头版","信息版","8","1","7"});
        list.add(new String[]{"金点子","头版","信息版","5","1","4"});
        list.add(new String[]{"金点子","头版","信息版","12","1","11"});
        for(String[] strs : list){//循环数据
            String[] strTemp=map.get(strs[1]);//判断是否已存在
            if(strTemp!=null){//存在就数据相加
                strTemp[3]=(Integer.parseInt(strTemp[3])+Integer.parseInt(strs[3]))+"";
                strTemp[4]=(Integer.parseInt(strTemp[4])+Integer.parseInt(strs[4]))+"";
                strTemp[5]=(Integer.parseInt(strTemp[5])+Integer.parseInt(strs[5]))+"";
            }else{//不存在就添加数据
                map.put(strs[1], strs);
            }
        }
        //迭代输出结果
        System.out.println("DM\t版面\t类型\t总数量\t已使用\t空闲");
        for(String key : map.keySet()){
            String[] strTemp=map.get(key);
            System.out.println(strTemp[0]+"\t"+strTemp[1]+"\t"+strTemp[2]+"\t"+strTemp[3]+"\t"+strTemp[4]+"\t"+strTemp[5]);
        }
    }
}