根据list集合设计类问题
像这样的 List 集合 java 类怎么设计
[
{
"recommendation_id": 586,
"status": 1,
"type": "explores",
"seq": 597,
"keyword_id": 848,
"name": "门头设计",
"urlname": "mentousheji",
"cover": {
"bucket": "hbfile",
"key": "dd3eb7af6bf69adfd8ee8be24703e9fe10041df61f164"
},
"description": "门头，是指企业、事业单位和个体工商户(以下简称单位)在门口设置的牌匾及相关设施。门头是一个商铺店门外的装饰形式。整体上说，制作精美的门头是美化销售场所和装饰店铺、吸引顾客的一种手段，是提升店面形象的重要方法。精心设计门头，是现代装饰的重要内容。",
"recommended_users": null,
"creator_id": null,
"is_hidden": 0,
"follow_count": 13,
"target_id": 848,
"title": "门头设计",
"url": "http://huaban.com/explore/mentousheji/"
},
{
"recommendation_id": 584,
"status": 1,
"type": "boards",
"seq": 194,
"board_id": 18682745,
"user_id": 327260,
"title": "◤各种黑白海报 | Black&White◢",
"description": "",
"category_id": "design",
"pin_count": 161,
"follow_count": 214,
"like_count": 1,
"created_at": 1417504894,
"updated_at": 1420450108,
"deleting": 0,
"is_private": 0,
"user": {
"username": "花蓉",
"urlname": "nininini757",
"pin_count": 20165,
"follow_count": 28573,
"user_id": 327260
},
"target_id": 18682745,
"cover": {
"bucket": "hbfile",
"key": "a81b9392c3a197d596ec9ae4d337535295554e9d1a2df"
},
"url": "http://huaban.com/boards/18682745/"
},
{
"recommendation_id": 583,
"status": 1,
"type": "users",
"seq": 594,
"user_id": 9893639,
"username": "我爱的人终变成我心里的针",
"urlname": "love734889400",
"created_at": 1379850964,
"avatar": {
"id": 29775572,
"farm": "farm1",
"bucket": "hbimg",
"key": "69706c1194d0cc588a948fdbfb4628227dc1292b163d-bW6ftL",
"type": "image/jpeg",
"width": 139,
"height": 144,
"frames": 1
},
"pin_count": 5222,
"follow_count": 30138,
"target_id": 9893639,
"cover": {
"bucket": "",
"key": ""
},
"title": "我爱的人终变成我心里的针",
"url": "http://huaban.com/love734889400/"
}
]用的是 GSON 转json已经有 Explores，Boards，Users 三个类设计了一个 Recommendation 类
recommendation数据库是 recommendation_id，status，type，seq，title，url 字段jackson 里面有一个 @JsonUnwrapped 注解
@JsonUnwrapped 作用在属性字段或方法上，用来将子JSON对象的属性添加到封闭的JSON对象如果没有@JsonUnwrapped，序列化后将为{"id":111,"name":{"firstName":"张","secondName":"三"}}反之：{"id":111,"firstName":"张","secondName":"三"}不这个 GSON 有没有这个方法
展开
收起
1
条回答
写回答
写回答
-
我说我不帅他们就打我，还说我虚伪json的键就是类的字段名，看见一个键后面是“{”就创建一个类，看见键后面是“[”就是一个List，这样就简单了。Recommendation里包含Cover、Avatar、User三个类，分别对应cover、avatar和user字段
//类定义public class Recommendation{ public long recommendationId; //... public User user; public Cover cover; public Avatar avatar; } public class User { private Long userId; private String username; ... } public class Cover { private String key; private String bucket; } public class Avatar{ private int id; // ... private int width; private int height; private int frames; }//解析 Gson gson = new Gson(); Type type = new TypeToken<List<Recommendation>>(){}.getType();//最外面是个List String json = "json内容";//String也可以是一个Reader List<Recommendation> = gson.fromJson(json,type); // TODO2019-07-17 18:49:50赞同 展开评论 打赏
版权声明：本文内容由阿里云实名注册用户自发贡献，版权归原作者所有，阿里云开发者社区不拥有其著作权，亦不承担相应法律责任。具体规则请查看《阿里云开发者社区用户服务协议》和《阿里云开发者社区知识产权保护指引》。如果您发现本社区中有涉嫌抄袭的内容，填写侵权投诉表单进行举报，一经查实，本社区将立刻删除涉嫌侵权内容。
相关问答
