Ajax中有什么方法吗？

代码如下

HintServlet.java(snippet)

EwebServlet（＂／Hint二）
public class HintServlet extends HttpServlet{
protected void processRequest(HttpServletRequest request,
HttpServletResponse response) throws ServletException, I0Exception(
Printwriter out-response.getwriter();
String hint"*;
string a[] = new String[30];
ə[Θ]- "Anna"; a[1] - "Brittany"; ə[2] - "Cinderella";

String q-request.getParameter("q"
if (q.length() >0) {
for (int 1= 0;1<30;1++)
if(a[1].indexof(q)>-0)
if (hint "
hint-a[i];
else
hint = hint+","+ a[1];
if (hint =="")
out.println("no suggestion");
else
out.println(hint);