问题
我“需要”计算期望传递给函数对象的参数数量。我的命令是通过它们的对象存储的,因此我可以分别引用每个命令。我已经尝试过检查,尽管它看起来很完美,但是由于某种原因,它不能区分两个输出均为0的自变量和1个自变量。似乎我必须链接实际的代码,因为我的个人脚本肯定是错误的。这是代码:
# ============== Impots ==============
from shlex import split
from inspect import getfullargspec
# ============== Main ==============
class Command:
def __init__(self, fn, name=None, aliases=None):
self.name = name or fn.__name__
self.aliases = aliases or []
self.fn = fn
def __call__(self, \*rgs, \*kwargs):
return self.fn(\*rgs, \*kwargs)
@property
def all_names(self):
return (self.name, \*elf.aliases)
# ============= Storage =============
class Commands(dict):
def __init__(self, not_found: str='{} was not recognized.', argmismatch: str='{} takes {} arguments but {} were given.'):
self.flag = [not_found, argmismatch]
super().__init__()
def _add_command(self, command):
for cmd_name in command.all_names:
if cmd_name in self:
raise ValueError(f'Name or alias assigned to function {command.fn.__name__} is duplicate: {cmd_name}')
self[cmd_name] = command
def add_command(self, name=None, aliases=None):
def inner_fn(fn):
self._add_command(Command(fn, name, aliases))
return fn
return inner_fn
def execute(self, user_input):
self.command, \*rgs = self.parse(user_input or 'no_input')
if self.command.lower() in self:
# THIS IS WHERE THE ISSUE HAPPENS
print(f'Passed: {len(args)}')
print(f'Expected: {len(getfullargspec(self[self.command])[0])}')
if not (len(args)==len(getfullargspec(self[self.command])[0])):
return (False, self.flag[1].format(self.command, len(getfullargspec(self[self.command])[0]), len(args)))
self[self.command](\*rgs)
return (True, 'Command found!')
else:
return (False, self.flag[0].format(self.command))
@staticmethod
def parse(string):
if (string=='no_input'):
return ['','']
return split(string)
cmd = Commands()
@cmd.add_command(name='foo')
def foo():
print('bar')
cmd.execute('foo bar')
不是问题 * I have already tried seeing if the list was filled with a ` Null ` value, it is not. * It does this across platforms (VSCode, Repl.it, PyDroid) so it is not a weird os issue. * I'm not sure if it could be ` len() ` treating it weirdly, but I know a normal empty list such as ` [] ` is counted as one. *我将其用于错误消息,并可能用于自动提示命令可能出了什么问题,我将乐意提供任何帮助,并会使用新信息以及可能的,正确的和不正确的解决方案来更新我的帖子。 * 类似帖子
这个帖子有类似的问题,但是提供的解决方案与我的要求不符。
问题来源:stackoverflow
如果只访问第零个元素,则不需要getfullargspec
。
my_funct。代码 .co_argcount
回答来源:stackoverflow
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