如何在同一行的for循环中返回列表的特定元素？（python 3）
ALL_IRELAND_WINNERS = [(1887, "Munster", "Tipperary"), (1889, "Leinster", "Dublin"), (1890, "Munster", "Cork"), (1891, "Munster", "Kerry"), (1892, "Munster", "Cork"), (1893, "Munster", "Cork"), (1894, "Munster", "Cork"), (1895, "Munster", "Tipperary"), (1896, "Munster", "Tipperary"), (1897, "Munster", "Limerick"), (1898, "Munster", "Tipperary"), (1899, "Munster", "Tipperary"), (1900, "Munster", "Tipperary"), (1901, "Britain", "London"), (1902, "Munster", "Cork"), (1903, "Munster", "Cork"), (1904, "Leinster", "Kilkenny"), (1905, "Leinster", "Kilkenny0]
query_team = input("Enter a county: ")
def winning_county(query_team):
for (years, province, county) in ALL_IRELAND_WINNERS:
if (query_team == county):
return(years)
用户输入的“县”将搜索此列表，并且只返回年份中的1年，我需要它返回他们赢得的所有年份并将它们放到列表中……有什么帮助吗？
问题来源：stackoverflow
写回答
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你近了 与其给出第一个正确答案，不如保留一份工作年份的清单，然后返回完整清单。所以像这样：
query_team = input("Enter a county: ") def winning_county(query_team): winning_years = [] for (year, province, county) in ALL_IRELAND_WINNERS: if (query_team == county): winning_years.append(year) return winning_years回答来源：stackoverflow
2020-03-24 22:29:48赞同 展开评论 打赏
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