甲队为a,b,c三人，乙队为x,y,z三人。已抽签决定比赛名单，如何找出每个人的对战选手

if __name__ == '__main__':
    w = [(i, j, k) for i in ['x', 'y', 'z'] for j in ['x', 'y', 'z'] for k in ['x', 'y', 'z']
         if i != j and j != k and i != k and i != 'x' and k not in ('x', 'z')]
    print('order is a -- %s\t b -- %s\tc--%s' % w[0])

#!/usr/bin/python
# -*- coding: UTF-8 -*-
 
for i in range(ord('x'),ord('z') + 1):
    for j in range(ord('x'),ord('z') + 1):
        if i != j:
            for k in range(ord('x'),ord('z') + 1):
                if (i != k) and (j != k):
                    if (i != ord('x')) and (k != ord('x')) and (k != ord('z')):
                        print 'order is a -- %s\t b -- %s\tc--%s' % (chr(i),chr(j),chr(k))

以上实例输出结果为：

order is a -- z     b -- x    c--y