Problem Description
Happy new year to everybody!
Now, I want you to guess a minimum number x betwwn 1000 and 9999 to let
(1) x % a = 0;
(2) (x+1) % b = 0;
(3) (x+2) % c = 0;
and a, b, c are integers between 1 and 100.
Given a,b,c, tell me what is the number of x ?
Input
The number of test cases c is in the first line of input, then c test cases followed.every test contains three integers a, b, c.
Output
For each test case your program should output one line with the minimal number x, you should remember that x is between 1000 and 9999. If there is no answer for x, output “Impossible”.
Sample Input
2
44 38 49
25 56 3
Sample Output
Impossible
2575
枚举就可以了。。
import java.util.Scanner; public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while (t-- > 0) { int a = sc.nextInt(); int b = sc.nextInt(); int c = sc.nextInt(); boolean is = true; int tm=a; while(a<1000){ a=a+tm; } //注意！答案的范围是[1000,9999] for (int i = a; i < 10000; i = i + tm) { //此处注意i是加tm，而不是再加a了，因为a可能变了。 if ((i+1)%b==0&&(i+2)%c==0) { System.out.println(i); is = false; break; } } if (is) { System.out.println("Impossible"); } } } }
