Java中数组的地址问题(hashCode解析)：

import java.util.Arrays;
public class Action1 {
  public static void main(String[] args) {
    //1、初始数组
    int [] array0= {5,9,9,9,65,65,95,9,5,6,69,6,65,899};
    System.out.println("0->生成地址:\t"+array0.hashCode());
    //2、赋值数组
    int [] array1=array0;
    System.out.println("1->未生成新地址:\t"+array1.hashCode());
    //3、创建数组相当于new
    int[] array2 = Arrays.copyOf(array0, array0.length);
    System.out.println("2->生成新地址:\t"+array2.hashCode());
    //4、new创建数组，相当于array2的Arrays.copyOf
    int[] array3 = new int[array0.length];
    for (int i = 0; i < array0.length; i++) {
      array3[i]=array0[i];
    }
    System.out.println("3->生成新地址:\t"+array3.hashCode());
  }
}