void itoa(int n, char *s)
{
int sign;
char *t = s;
if ((sign = n) < 0)
n = -n;
do
{
*s++ = n % 10 + '0';
}
while ((n /= 10) >0);
if (sign < 0)
*s++ = '-';
*s = '\0';
reverse(t);
}
void reverse(char *s)
{
int c;
char *t;
for (t = s + (strlen(s) - 1); s < t; s++, t-- )
{
c = *s;
*s = *t;
*t = c;
}
}
原文来自：http://blog.21ic.com/user1/5433/archives/2008/54208.html
本文转自 Linux_woniu 51CTO博客，原文链接:http://blog.51cto.com/linuxcgi/1965340
