求极限 $$\bex \vlm{n}\dfrac{(n^2+1)(n^2+2)\cdots(n^2+n)}{(n^2-1)(n^2-2)\cdots(n^2-n)}. \eex$$
解答: 还记得对数不等式么: $$\bex \dfrac{x}{1+x}<\ln(1+x)<x,\quad x>0. \eex$$ 我们有 $$\beex \bea \ln\dfrac{n^2+i}{n^2-i}&=\ln\sex{1+\dfrac{2i}{n^2-i}} <\dfrac{2i}{n^2-i}\leq \dfrac{2i}{n^2-n},\\ \ln\dfrac{n^2+i}{n^2-i}&>\dfrac{\dfrac{2i}{n^2-i}}{1+\dfrac{2i}{n^2-i}} =\dfrac{2i}{n^2+i}\geq \dfrac{2i}{n^2+n}. \eea \eeex$$ 相加而有 $$\bex 1< \ln \prod_{k=1}^n \dfrac{n^2+i}{n^2-i}<\dfrac{n^2+n}{n^2-n}. \eex$$ 令 $n\to\infty$ 即得原极限 $=e$.
