C++代码来计算一个点围绕另一个点旋转45度后的坐标

#include <iostream>
#include <cmath>

struct Point {
    double x;
    double y;
};

// 计算点p围绕点center逆时针旋转angle度后的新坐标
Point rotatePoint(const Point& p, const Point& center, double angle) {
    double radians = angle * M_PI / 180.0; // 将角度转换为弧度
    double cosValue = std::cos(radians);
    double sinValue = std::sin(radians);

    // 应用旋转矩阵变换
    double newX = (p.x - center.x) * cosValue - (p.y - center.y) * sinValue + center.x;
    double newY = (p.x - center.x) * sinValue + (p.y - center.y) * cosValue + center.y;

    return { newX, newY };
}

int main() {
    Point p{ 1.0, 1.0 }; // 需要旋转的点的坐标
    Point center{ 0.0, 0.0 }; // 中心点的坐标

    double angle = 45.0; // 旋转角度

    Point rotatedPoint = rotatePoint(p, center, angle);

    std::cout << "旋转后的坐标: (" << rotatedPoint.x << ", " << rotatedPoint.y << ")" << std::endl;

    return 0;
}