poj 2105 IP Address

简介: 题目链接
//poj 2105
//2013-05-01-21.10
#include <stdio.h>
char s[34];
int a[8] = {128, 64, 32, 16, 8, 4, 2, 1};
int main()
{
    int n;
    scanf("%d", &n);
    while (n--)
    {
        scanf("%s", s);
        int ans = 0;
        int f = 1;
        for (int i = 0; i < 32; i++)
        {
            if (s[i] == '1')
                ans += a[i%8];
            if ((i+1) % 8 == 0)
            {
                if (f)
                {
                    f = 0;
                    printf("%d", ans);
                }
                else
                    printf(".%d", ans);
                ans = 0;
            }
        }
        puts("");
    }
    return 0;
}
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