【PAT甲级 - C++题解】1027 Colors in Mars

1027 Colors in Mars

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:

Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:

For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.

Sample Input:

15 43 71
• 1

Sample Output:

#123456

题意

给定三个十进制数，让我们将他们转换成十三进制（0~9,A~C）并输出，如果给定的十进制数转换成十三进制只有一位，那么在前面还需要补一个 0 ，例如十进制 10 转换成十三进制输出 0A 。

思路

1. 用数组输入三个十进制数，方便后续处理。
2. 将每个十进制数转换两位十三进制的数，第一位用十进制数除以 13 ，第二位则用十进制数余上 13

代码

#include<bits/stdc++.h>
using namespace std;
char get(int x)
{
    if (x >= 10)   return x - 10 + 'A';
    return x + '0';
}
int main()
{
    int a[3];
    for (int i = 0; i < 3; i++)    cin >> a[i];
    cout << "#";
    for (int i = 0; i < 3; i++)    cout << get(a[i] / 13) << get(a[i] % 13);
    return 0;
}