简单做了一个android的project
想能过以下代码取得摸拟器的IP:
public String getLocalIpAddress() { try { for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) { NetworkInterface intf = en.nextElement(); for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) { InetAddress inetAddress = enumIpAddr.nextElement(); if (!inetAddress.isLoopbackAddress()) { return inetAddress.getHostAddress().toString(); } } } } catch (SocketException ex) { //Log.e(S.TAG, ex.toString()); } return null; }
运行结果,为NULL,百思不得其解,
尝试方法二:
try { Socket socket = new Socket("www.droidnova.com", 80); Log.i("", socket.getLocalAddress().toString()); } catch (Exception e) { Log.i("", e.getMessage()); }
同样无解.晕
万事,还真是开头难.
找STORM哥帮手:
修改XML如下:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.test.main"
android:versionCode="1"
android:versionName="1.0">
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".hello"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
<uses-sdk android:minSdkVersion="8" />
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
</manifest>
重点在红色部分.解决,记录
