【C语言】百元百鸡 经典双循环问题

#include <stdio.h>
int main() {
  int gong, mu, xiao, n, m;
  m = 100; n = 100;
  for (gong = 0; gong <= n / 5; gong++) {
    for (mu = 0; mu <= n / 3; mu++) {
      xiao = n - gong - mu;
      if (gong * 5 + mu * 3 + xiao / 3 == m && mu + gong + xiao == n && xiao % 3 == 0) {
        printf("公鸡个数%d,母子个数%d,小鸡个数%d.\n", gong, mu, xiao);
      }
    }
  }
  return 0;
}