C语言利用递归实现整数次幂出错

#include <stdio.h>
#include <stdlib.h>

int show(int number,int count);
int main()
{
    int count;
    int number;
    while(scanf("%d%d",&number,&count)==2){
        if(number==0){
            printf("the answer is 0");
        }
        else{
            if(count==0){
                printf("the answer is 1");
            }
            if(count>0){
                printf("the answer is %d\n",show(number,count));
            }
        }
        printf("please try again:");
    }
    return 0;
}
int show(int number,int count){
    if(count>0)
        return show(number,(count-1))*number;
}
它的运行结果不对，查了好久看不出来为什么。

更奇怪的是把上述所有类型换成double以后，乱码了

全选复制放进笔记#include <stdio.h>
#include <stdlib.h>

double  show(double  number,double count);
int main()
{
    double count;
    double number;

    while(scanf("%lf%lf",&number,&count)==2){
        if(number==0){
            printf("the answer is 0");
        }
        else{
            if(count==0){
                printf("the answer is 1");
            }
            if(count>0){
                printf("the answer is %f\n",show(number,count));
            }
        }
        printf("please try again:");
    }
    return 0;
}
double show(double number,double count){
    if(count>0)
        return show(number,(count-1))*number;
}