开发者社区> 问答> 正文

UILocalNotification单击事件的问题

代码如下:

- (void) socketIO:(SocketIO *)socket didReceiveEvent:(SocketIOPacket *)packet
{
NSLog(@"didReceiveEvent(),%@",packet.data );



SysNotification *sysNotification=[GlobalVariable parseSysNotificationWithString:packet.data];


UILocalNotification *alarm = [[UILocalNotification alloc] init];
if (alarm) {
    alarm.fireDate = [NSDate date];
    alarm.timeZone = [NSTimeZone defaultTimeZone];
    alarm.repeatInterval = 0;
    alarm.soundName = UILocalNotificationDefaultSoundName;
    alarm.alertBody = @"Test message...";

    NSDictionary *infoDic = [NSDictionary dictionaryWithObject:@"name" forKey:@"key"];
    alarm.userInfo = infoDic;


    [[UIApplication sharedApplication] presentLocalNotificationNow:alarm];
}


}

我需要实现的是点击状态栏的UILocalNotification,出现一些视图控制器。怎么实现?

展开
收起
爵霸 2016-05-27 11:44:59 1862 0
1 条回答
写回答
取消 提交回答
  • 处理本地通知有两个情况:

    1,通过点击本地通知应用启动。

    -(BOOL)application:(UIApplication *)app didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
    
        UILocalNotification *localNotif =
    
            [launchOptions objectForKey:UIApplicationLaunchOptionsLocalNotificationKey];
    
        if (localNotif) {
    
           //load your controller
    
        }
    
        return YES;
    
    }

    2.应用是活动的,就把下面的代码加到AppDelegate中

       -(void)application:(UIApplication *)app didReceiveLocalNotification:(UILocalNotification *)notif {
    
            //加载controller
    
        }
    2019-07-17 19:17:36
    赞同 展开评论 打赏
问答地址:
问答排行榜
最热
最新

相关电子书

更多
低代码开发师(初级)实战教程 立即下载
冬季实战营第三期:MySQL数据库进阶实战 立即下载
阿里巴巴DevOps 最佳实践手册 立即下载