String url = "http://172.16.108.8:8080/SunShine/PinglunInfo.action?name=济南市第五人民医院& amp;address=山东省济南市槐荫区经十路447号, China&page=0"
HttpClient client = new DefaultHttpClient();
HttpPost request = new HttpPost(url);
System.out.println(request.toString() + "request.tostring");
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
String out = EntityUtils.toString(entity);
经过我测试,我的这个url有问题,url包含逗号,导致发送不到服务端,我换了一个没有逗号的,就可以发送过去了,,纠结。。这个问题该怎么解决。。。。。求解决,,,,
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将中文参数直接放在URL中,需要做 URLEncode 处理的:URLEncoder.encode(...),可以使用 UrlEncodedFormEntity来添加参数,使用方法请看: http://www.oschina.net/code/snippet_12_5909######O(∩_∩)O哈哈~,谢谢站长、、######
try {
String storeName = URLDecoder.decode(request.getParameter("name"), "utf-8");
String storeAddress = URLDecoder.decode(request.getParameter("address"),"utf-8");
String currentPage = request.getParameter("page");
String sql =.......;
CoordService coordService = new CoordService();
try {
String xmlAddress = coordService.getAll(sql);
System.out.println(xmlAddress
+ "------------------------------------------------");
this.response.getWriter().write(xmlAddress);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
我的客户端代码
public static String getCritisimUrl(String url,
List<BasicNameValuePair> params) throws Exception {
DefaultHttpClient mHttpClient = new DefaultHttpClient();
System.out.println(url + "url------------");
HttpPost httpRequest = new HttpPost(new URI(url));
httpRequest.setEntity(new UrlEncodedFormEntity(params,"utf-8"));
HttpResponse response = mHttpClient.execute(httpRequest);
HttpEntity entity = response.getEntity();
String out = EntityUtils.toString(entity);
return out;
}
String url = "http://172.16.108.8:8080/SunShine/PinglunInfo.action";
List<BasicNameValuePair> params = new ArrayList<BasicNameValuePair>();
params.add(new BasicNameValuePair("name",URLEncoder.encode(title.getText().toString())));
params.add(new BasicNameValuePair("address", URLEncoder.encode(address.getText().toString().substring(4))));
params.add(new BasicNameValuePair("page",URLEncoder.encode(String.valueOf(currentPage))));
String out = getCritisimUrl(url, params);
返回的out是?? ,(乱码)。。。但是服务端我打印的那个xmlAddress 是中文。。怎么到了手机上就是乱码了呢
我用new String(result.getBytes("utf-8"), "gbk");也不行。几乎常见的编码都试了。。都试了。还是不行。
求解决、、、、、、!!!