查询以在Django中发送帖子请求
我正在尝试创建一个卡路里信息API，以节省用户的卡路里摄入量。
- If it is a new user, then add an entry for the user id and item id.
-
If the user already exists,
- If the item is new, then just map the item id and the calorie count with that user.
-
If the item id is already mapped with that user, then add the items calorie count with that item for that user.
Url: /api/calorie-info/save/Method: POST, Input: { "user_id": 1, "calorie_info": [{ "itemId": 10, "calorie_count": 100 }, { "itemId": 11, "calorie_count": 100 }] }
Output: - Response Code: 201
我的模特：
class CalorieInfo(models.Model):
user_id = models.IntegerField(unique=True)
itemId = models.IntegerField(unique=True)
calorie_count = models.IntegerField()
我试过了：
class Calorie(APIView):
def post(self, request):
data = json.loads(request.body.decode("utf-8"))
user_id = data['user_id']
for i in data['calorie_info']:
entry = CalorieInfo(user_id=user_id, item_id=i['itemId'], calorie=i['calorie_count'])
entry.save()
res = {"status": "success"}
return Response(res, status=status.HTTP_201_CREATED)
上面的代码工作正常，但是如何检查代码中的上述条件？
问题来源：stackoverflow
展开
收起
1
条回答
写回答
写回答
-
您需要像这样检查：
def post(self, request): data = json.loads(request.body.decode("utf-8")) user_id = data['user_id'] # fetch calorieinfo object for given user user_calorieinfo = CalorieInfo.objects.filter(user_id=user_id) # if user exists if user_calorieinfo: # ifCalorieInfo item mapped with user for i in data['calorie_info']: if CalorieInfo.objects.filter(user_id=user_id,itemId=i['itemId']: for obj in CalorieInfo.objects.filter(user_id=user_id,itemId=i['itemId']): updated_count = obj.calorie_count + i['calorie_count'] CalorieInfo.objects.filter(user_id=user_id,itemId=i['itemId']).update(calorie_count= updated_count) else: entry = CalorieInfo(user_id=user_id, item_id=i['itemId'], calorie=i['calorie_count']) entry.save() else: for i in data['calorie_info']: entry = CalorieInfo(user_id=user_id, item_id=i['itemId'], calorie=i['calorie_count']) entry.save() res = {"status": "success"} return Response(res, status=status.HTTP_201_CREATED)希望这会成功！
#for getting CalorieInfo object def get(self): id = request.GET.get('user_id') user_calorieinfo = CalorieInfo.objects.filter(user_id=user_id) response["user_id"] = id response["calorie_info"] = [] for obj in user_calorieinfo: response["calorie_info"].append({"itemId":obj.itemID, "calorie_count":obj.calorie_count}) response["status"] = success return Response(response, status=status.HTTP_200_OK)回答来源：stackoverflow
2020-03-24 09:43:36赞同 展开评论 打赏
版权声明：本文内容由阿里云实名注册用户自发贡献，版权归原作者所有，阿里云开发者社区不拥有其著作权，亦不承担相应法律责任。具体规则请查看《阿里云开发者社区用户服务协议》和《阿里云开发者社区知识产权保护指引》。如果您发现本社区中有涉嫌抄袭的内容，填写侵权投诉表单进行举报，一经查实，本社区将立刻删除涉嫌侵权内容。
相关问答
