hibernate 的问题啊

用DetachedCriteria类 组装查询条件，咋个生成这样的sql语句了捏？ 如果没没条件的话还行 ，一加上where条件查询，就会出 where y1_.... 然后就报错：列名 'y1_' 无效。上一段打印出的sql

select top 14 this_.id as y0_, this_.CODE as y1_, this_.PROJECT_NAME as y2_, this_.PROJECT_STATE as y3_, this_.PROJECT_CLASS as y4_, this_.CUSTOMER_ID as y5_, this_.CUSTOMER_DEPARTMENT_MAIN as y6_, this_.CUSTOMER_DEPARTMENT_HELP as y7_, this_.CUSTOMER_LINKMAN as y8_, this_.CUSTOMER_LINKMAN_PHONE as y9_, this_.CUSTOMER_CODE as y10_, this_.UNIT_PLAN as y11_, this_.UNIT_PLAN_LINKMAN as y12_, this_.UNIT_PLAN_LINKMAN_PHONE as y13_, this_.SUPERVISOR as y14_, this_.SUPERVISOR_LINKMAN as y15_, this_.SUPERVISOR_LINKMAN_PHONE as y16_, this_.PROJECT_CUSTODIAN as y17_, this_.PROJECT_DEPARTMENT as y18_, this_.PROJECT_DEPARTMENT_CUSTODIAN as y19_, this_.PROJECT_MANAGER as y20_, this_.SAFETY_OFFICER as y21_, this_.QUALITY_INSPECTOR as y22_, this_.LIBRARIAN as y23_, this_.BULIDERS as y24_, this_.MATERIALMAN as y25_, this_.TECHONLOGY as y26_, this_.FILE_TRANSFER as y27_, this_.BUILD_STATE as y28_, this_.COMPANYMANAGE_ID as y29_, this_.PROJECT_DATE as y30_, this_.USER_ID as y31_, this_.ACCESSORY_NAME as y32_ from project this_ where (y1_ like ? and y2_ like ?) order by y1_ desc