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如何在Python中查找或删除列表中的子串列表

我有一个子字符串列表,我将从另一个列表中删除, mylist

mylist = ['abc123', 'def456', 'ghi789','ghi123']

sub = ['123','456']
print ([s for s in mylist if sub[j] in s for j in sub])
这给出了错误。有没有其他方法可以找到这个。

预期产量:

['abc123','ghi123','def456']
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一码平川MACHEL 2019-02-28 14:44:03 4818 0
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  • 使用python set可以使程序更简洁
    mylist = ['abc123', 'def456', 'ghi789','ghi123',"123"]

    sub = ['123','456']

    print(list(set(mylist)-set(sub)))

    2019-07-17 23:29:48
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  • mylist = ['abc123', 'def456', 'ghi789','ghi123']
    sub = ['123','456']
    new_list = []

    先确定正常的写法

    for my_str in mylist:

    for sub_str in sub:
        if sub_str in my_str:
            new_list.append(my_str)

    print new_list

    然后在理解这颗语法糖

    print [j for i in range(5) for j in range(i)]

    最后改写下

    print [my_str for my_str in mylist for sub_str in sub if sub_str in my_str]

    2019-07-17 23:29:48
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  • 你需要

    mylist = ['abc123', 'def456', 'ghi789','ghi123']
    sub = ['123','456']

    print ([i for i in mylist for j in sub if j in i])
    输出:

    ['abc123', 'def456', 'ghi123']

    2019-07-17 23:29:47
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