Problem Description：

A number of students sit in a circle facing their teacher in the center. Each student initially has an even number of pieces of candy. When the teacher blows a whistle, each student simultaneously gives half of his or her candy to the neighbor on the right. Any student, who ends up with an odd number of pieces of candy, is given another piece by the teacher. The game ends when all students have the same number of pieces of candy.

Write a program which determines the number of times the teacher blows the whistle and the final number of pieces of candy for each student from the amount of candy each child starts with.

Input：

The input may describe more than one game. For each game, the input begins with the number N of students, followed by N (even) candy counts for the children counter-clockwise around the circle. The input ends with a student count of 0. Each input number is on a line by itself.

Output：

For each game, output the number of rounds of the game followed by the amount of candy each child ends up with, both on one line.

Sample Input：

6

36

2

2

2

2

2

11

22

20

18

16

14

12

10

8

6

4

2

4

2

4

6

8

0

Sample Output：

15 14

17 22

4 8

解题思路：

就是按照逆时针去模拟给糖果的过程，注意先把自己的糖果给别人，再从别人那里获得，主要边界处理，就是a[0]和a[n-1]的关系就可以了，简单的模拟题。。。

程序代码：

#include<stdio.h>
#define N 1001
int a[N];
int main()
{
  int n,i,ans,t;
  while(scanf("%d",&n),n)
  {
    for(i=0;i<n;i++)
      scanf("%d",&a[i]);
    ans=0;
    while(1)
    {
      for(i=1;i<n;i++)
        if(a[i-1]!=a[i])
          break;
      if(i>=n)
        break;
      ans++;
      t=a[n-1]/2;
      for(i=n-1;i>0;i--)
      {
        a[i]/=2;
        a[i]+=a[i-1]/2;
      }
      a[0]/=2;
      a[0]+=t;
      for(i=0;i<n;i++)
        if(a[i]&1)
          a[i]++;
    }
    printf("%d %d\n",ans,a[0]);
  }
  return 0;
}