4 - Forward propagation module
4.1 - Linear Forward
Now that you have initialized your parameters, you will do the forward propagation module. You will start by implementing some basic functions that you will use later when implementing the model. You will complete three functions in this order:
- LINEAR
- LINEAR -> ACTIVATION where ACTIVATION will be either ReLU or Sigmoid.
- [LINEAR -> RELU] $\times$ (L-1) -> LINEAR -> SIGMOID (whole model)
The linear forward module (vectorized over all the examples) computes the following equations:
$$Z^{[l]} = W{[l]}A{[l-1]} +b^{[l]}\tag{4}$$
where $A^{[0]} = X$.
Exercise: Build the linear part of forward propagation.
Reminder:
The mathematical representation of this unit is $Z^{[l]} = W{[l]}A{[l-1]} +b^{[l]}$. You may also find np.dot() useful. If your dimensions don't match, printing W.shape may help.
# GRADED FUNCTION: linear_forward def linear_forward(A, W, b): """ Implement the linear part of a layer's forward propagation. Arguments: A -- activations from previous layer (or input data): (size of previous layer, number of examples) W -- weights matrix: numpy array of shape (size of current layer, size of previous layer) b -- bias vector, numpy array of shape (size of the current layer, 1) Returns: Z -- the input of the activation function, also called pre-activation parameter cache -- a python dictionary containing "A", "W" and "b" ; stored for computing the backward pass efficiently """ ### START CODE HERE ### (≈ 1 line of code) Z = np.dot(W,A)+b ### END CODE HERE ### assert(Z.shape == (W.shape[0], A.shape[1])) cache = (A, W, b) return Z, cache
A, W, b = linear_forward_test_case() Z, linear_cache = linear_forward(A, W, b) print("Z = " + str(Z))
Z = [[ 3.26295337 -1.23429987]]
Expected output:
<table style="width:35%">
<tr>
<td> Z </td>
<td> [[ 3.26295337 -1.23429987]] </td>
</tr>
</table>
4.2 - Linear-Activation Forward
In this notebook, you will use two activation functions:
- Sigmoid: $\sigma(Z) = \sigma(W A + b) = \frac{1}{ 1 + e^{-(W A + b)}}$. We have provided you with the
sigmoidfunction. This function returns two items: the activation value "a" and a "cache" that contains "Z" (it's what we will feed in to the corresponding backward function). To use it you could just call:
A, activation_cache = sigmoid(Z)
- ReLU: The mathematical formula for ReLu is $A = RELU(Z) = max(0, Z)$. We have provided you with the
relufunction. This function returns two items: the activation value "A" and a "cache" that contains "Z" (it's what we will feed in to the corresponding backward function). To use it you could just call:
A, activation_cache = relu(Z)
For more convenience, you are going to group two functions (Linear and Activation) into one function (LINEAR->ACTIVATION). Hence, you will implement a function that does the LINEAR forward step followed by an ACTIVATION forward step.
Exercise: Implement the forward propagation of the LINEAR->ACTIVATION layer. Mathematical relation is: $A^{[l]} = g(Z^{[l]}) = g(W{[l]}A{[l-1]} +b^{[l]})$ where the activation "g" can be sigmoid() or relu(). Use linear_forward() and the correct activation function.
# GRADED FUNCTION: linear_activation_forward def linear_activation_forward(A_prev, W, b, activation): """ Implement the forward propagation for the LINEAR->ACTIVATION layer Arguments: A_prev -- activations from previous layer (or input data): (size of previous layer, number of examples) W -- weights matrix: numpy array of shape (size of current layer, size of previous layer) b -- bias vector, numpy array of shape (size of the current layer, 1) activation -- the activation to be used in this layer, stored as a text string: "sigmoid" or "relu" Returns: A -- the output of the activation function, also called the post-activation value cache -- a python dictionary containing "linear_cache" and "activation_cache"; stored for computing the backward pass efficiently """ if activation == "sigmoid": # Inputs: "A_prev, W, b". Outputs: "A, activation_cache". ### START CODE HERE ### (≈ 2 lines of code) Z, linear_cache = linear_forward(A_prev, W, b) A, activation_cache = A,activation_cache = sigmoid(Z) ### END CODE HERE ### elif activation == "relu": # Inputs: "A_prev, W, b". Outputs: "A, activation_cache". ### START CODE HERE ### (≈ 2 lines of code) Z, linear_cache = linear_forward(A_prev, W, b) A, activation_cache = A,activation_cache = relu(Z) ### END CODE HERE ### assert (A.shape == (W.shape[0], A_prev.shape[1])) cache = (linear_cache, activation_cache) return A, cache
A_prev, W, b = linear_activation_forward_test_case() A, linear_activation_cache = linear_activation_forward(A_prev, W, b, activation = "sigmoid") print("With sigmoid: A = " + str(A)) A, linear_activation_cache = linear_activation_forward(A_prev, W, b, activation = "relu") print("With ReLU: A = " + str(A))
With sigmoid: A = [[ 0.96890023 0.11013289]] With ReLU: A = [[ 3.43896131 0. ]]
Expected output:
<table style="width:35%">
<tr>
<td> **With sigmoid: A ** </td>
<td > [[ 0.96890023 0.11013289]]</td>
</tr>
<tr>
<td> **With ReLU: A ** </td>
<td > [[ 3.43896131 0. ]]</td>
</tr>
</table>
Note: In deep learning, the "[LINEAR->ACTIVATION]" computation is counted as a single layer in the neural network, not two layers.
d) L-Layer Model
For even more convenience when implementing the $L$-layer Neural Net, you will need a function that replicates the previous one (linear_activation_forward with RELU) $L-1$ times, then follows that with one linear_activation_forward with SIGMOID.
<caption><center> Figure 2 : [LINEAR -> RELU] $\times$ (L-1) -> LINEAR -> SIGMOID model</center></caption>
Exercise: Implement the forward propagation of the above model.
Instruction: In the code below, the variable AL will denote $A^{[L]} = \sigma(Z^{[L]}) = \sigma(W^{[L]} A^{[L-1]} + b^{[L]})$. (This is sometimes also called Yhat, i.e., this is $\hat{Y}$.)
Tips:
- Use the functions you had previously written
- Use a for loop to replicate [LINEAR->RELU] (L-1) times
- Don't forget to keep track of the caches in the "caches" list. To add a new value
cto alist, you can uselist.append(c).
# GRADED FUNCTION: L_model_forward def L_model_forward(X, parameters): """ Implement forward propagation for the [LINEAR->RELU]*(L-1)->LINEAR->SIGMOID computation Arguments: X -- data, numpy array of shape (input size, number of examples) parameters -- output of initialize_parameters_deep() Returns: AL -- last post-activation value caches -- list of caches containing: every cache of linear_relu_forward() (there are L-1 of them, indexed from 0 to L-2) the cache of linear_sigmoid_forward() (there is one, indexed L-1) """ caches = [] A = X L = len(parameters) // 2 # number of layers in the neural network # Implement [LINEAR -> RELU]*(L-1). Add "cache" to the "caches" list. for l in range(1, L): A_prev = A ### START CODE HERE ### (≈ 2 lines of code) A, cache = linear_activation_forward(A_prev,parameters["W"+str(l)],parameters["b"+str(l)],activation="relu") caches.append(cache) ### END CODE HERE ### # Implement LINEAR -> SIGMOID. Add "cache" to the "caches" list. ### START CODE HERE ### (≈ 2 lines of code) AL, cache = linear_activation_forward(A,parameters["W"+str(L)],parameters["b"+str(L)],activation="sigmoid") caches.append(cache) ### END CODE HERE ### assert(AL.shape == (1,X.shape[1])) return AL, caches
X, parameters = L_model_forward_test_case() AL, caches = L_model_forward(X, parameters) print("AL = " + str(AL)) print("Length of caches list = " + str(len(caches)))
AL = [[ 0.17007265 0.2524272 ]] Length of caches list = 2
<table style="width:40%">
<tr>
<td> AL </td>
<td > [[ 0.17007265 0.2524272 ]]</td>
</tr>
<tr>
<td> **Length of caches list ** </td>
<td > 2</td>
</tr>
</table>
Great! Now you have a full forward propagation that takes the input X and outputs a row vector $A^{[L]}$ containing your predictions. It also records all intermediate values in "caches". Using $A^{[L]}$, you can compute the cost of your predictions.
5 - Cost function
Now you will implement forward and backward propagation. You need to compute the cost, because you want to check if your model is actually learning.
Exercise: Compute the cross-entropy cost $J$, using the following formula: $$-\frac{1}{m} \sum\limits_{i = 1}^{m} (y{(i)}\log\left(a{[L] (i)}\right) + (1-y^{(i)})\log\left(1- a^{L}\right)) \tag{7}$$
# GRADED FUNCTION: compute_cost def compute_cost(AL, Y): """ Implement the cost function defined by equation (7). Arguments: AL -- probability vector corresponding to your label predictions, shape (1, number of examples) Y -- true "label" vector (for example: containing 0 if non-cat, 1 if cat), shape (1, number of examples) Returns: cost -- cross-entropy cost """ m = Y.shape[1] # Compute loss from aL and y. ### START CODE HERE ### (≈ 1 lines of code) cost = (-1/m)*np.sum(Y*np.log(AL)+(1-Y)*np.log(1-AL)) ### END CODE HERE ### cost = np.squeeze(cost) # To make sure your cost's shape is what we expect (e.g. this turns [[17]] into 17). assert(cost.shape == ()) return cost
Y, AL = compute_cost_test_case() print("cost = " + str(compute_cost(AL, Y)))
cost = 0.414931599615
Expected Output:
<table>
<tr> <td>**cost** </td> <td> 0.41493159961539694</td> </tr>
</table>
