Java Web中如何获取请求体内容呢？
我们知道请求方式分为两种：Get，Post
Java代码
- /***
- * Compatible with GET and POST
- *
- * @param request
- * @return : <code>byte[]</code>
- * @throws IOException
- */
- public static byte[] getRequestQuery(HttpServletRequest request)
- throws IOException {
- String submitMehtod = request.getMethod();
- String queryString = null;
- if (submitMehtod.equals("GET")) {// GET
- queryString = request.getQueryString();
- String charEncoding = request.getCharacterEncoding();// charset
- if (charEncoding == null) {
- charEncoding = "UTF-8";
- }
- return queryString.getBytes(charEncoding);
- } else {// POST
- return getRequestPostBytes(request);
- }
- }
- /***
- * Get request query string, form method : post
- *
- * @param request
- * @return byte[]
- * @throws IOException
- */
- public static byte[] getRequestPostBytes(HttpServletRequest request)
- throws IOException {
- int contentLength = request.getContentLength();
- if(contentLength<0){
- return null;
- }
- byte buffer[] = new byte[contentLength];
- for (int i = 0; i < contentLength;) {
- int readlen = request.getInputStream().read(buffer, i,
- contentLength - i);
- if (readlen == -1) {
- break;
- }
- i += readlen;
- }
- return buffer;
- }
- /***
- * Get request query string, form method : post
- *
- * @param request
- * @return
- * @throws IOException
- */
- public static String getRequestPostStr(HttpServletRequest request)
- throws IOException {
- byte buffer[] = getRequestPostBytes(request);
- String charEncoding = request.getCharacterEncoding();
- if (charEncoding == null) {
- charEncoding = "UTF-8";
- }
- return new String(buffer, charEncoding);
- }
说明：当请求方式为“Get”时，直接使用request.getQueryString()获取String
当请求方式为“Post”时，读取InputStream（request.getInputStream()）
