SQL练习题1

简介: create table student(sno varchar2(10) primary key,sname varchar2(20),sage number(2),ssex varchar2(5));create table teacher(tno varchar2(10)...
create table student(
sno varchar2(10) primary key,
sname varchar2(20),
sage number(2),
ssex varchar2(5)
);
create table teacher(
tno varchar2(10) primary key,
tname varchar2(20)
);
create table course(
cno varchar2(10),
cname varchar2(20),
tno varchar2(20),
constraint pk_course primary key (cno,tno)
);
create table sc(
sno varchar2(10),
cno varchar2(10),
score number(4,2),
constraint pk_sc primary key (sno,cno)
);
/*******初始化学生表的数据******/
insert into student values ('s001','张三',23,'男');
insert into student values ('s002','李四',23,'男');
insert into student values ('s003','吴鹏',25,'男');
insert into student values ('s004','琴沁',20,'女');
insert into student values ('s005','王丽',20,'女');
insert into student values ('s006','李波',21,'男');
insert into student values ('s007','刘玉',21,'男');
insert into student values ('s008','萧蓉',21,'女');
insert into student values ('s009','陈萧晓',23,'女');
insert into student values ('s010','陈美',22,'女');
commit;
/******************初始化教师表***********************/
insert into teacher values ('t001', '刘阳');
insert into teacher values ('t002', '谌燕');
insert into teacher values ('t003', '胡明星');
commit;
/***************初始化课程表****************************/
insert into course values ('c001','J2SE','t002');
insert into course values ('c002','Java Web','t002');
insert into course values ('c003','SSH','t001');
insert into course values ('c004','Oracle','t001');
insert into course values ('c005','SQL SERVER 2005','t003');
insert into course values ('c006','C#','t003');
insert into course values ('c007','JavaScript','t002');
insert into course values ('c008','DIV+CSS','t001');
insert into course values ('c009','PHP','t003');
insert into course values ('c010','EJB3.0','t002');
commit;
/***************初始化成绩表***********************/
insert into sc values ('s001','c001',78.9);
insert into sc values ('s002','c001',80.9);
insert into sc values ('s003','c001',81.9);
insert into sc values ('s004','c001',60.9);
insert into sc values ('s001','c002',82.9);
insert into sc values ('s002','c002',72.9);
insert into sc values ('s003','c002',81.9);
insert into sc values ('s001','c003','59');
commit;


练习:
注意:以下练习中的数据是根据初始化到 数据库 中的数据来写的SQL 语句,请大家务必注意。
 
 

1、查询“c001”课程比“c002”课程成绩高的所有学生的学号;

select a.* from
(select * from sc a where a.cno='c001') a,
(select * from sc b where b.cno='c002') b
where a.sno=b.sno and a.score > b.score;
*********************************
select * from sc a
where a.cno='c001'
and  exists(select * from sc b where b.cno='c002' and a.score>b.score
and a.sno = b.sno)

2、查询平均成绩大于60 分的同学的学号和平均成绩;

select sno,avg(score) from sc  group by sno having avg(score)>60;

3、查询所有同学的学号、姓名、选课数、总成绩;

select a.*,s.sname from (select sno,sum(score),count(cno) from sc group by sno) a ,student s where a.sno=s.sno

4、查询姓“刘”的老师的个数;

select count(*) from teacher where tname like '刘%';

5、查询没学过“谌燕”老师课的同学的学号、姓名;

select a.sno,a.sname from student a
where a.sno
not in
(select distinct s.sno
 from sc s,
      (select c.*
       from course c ,
           (select tno
            from teacher t
            where tname='谌燕')t
       where c.tno=t.tno) b
  where s.cno = b.cno )
 

6、查询学过“c001”并且也学过编号“c002”课程的同学的学号、姓名;

select st.* from sc a
join sc b on a.sno=b.sno
join student st
on st.sno=a.sno
where a.cno='c001' and b.cno='c002' and st.sno=a.sno;

7、查询学过“谌燕”老师所教的所有课的同学的学号、姓名;

select st.* from student st join sc s on st.sno=s.sno
join course c on s.cno=c.cno
join teacher t on c.tno=t.tno
where t.tname='谌燕'

8、查询课程编号“c002”的成绩比课程编号“c001”课程低的所有同学的学号、姓名;

select * from student st
join sc a on st.sno=a.sno
join sc b on st.sno=b.sno
where a.cno='c002' and b.cno='c001' and a.score < b.score

9、查询所有课程成绩小于60 分的同学的学号、姓名;

select st.*,s.score from student st
join sc s on st.sno=s.sno
join course c on s.cno=c.cno
where s.score <60

10、查询没有学全所有课的同学的学号、姓名;

select stu.sno,stu.sname,count(sc.cno) from student stu
left join sc on stu.sno=sc.sno
group by stu.sno,stu.sname
having count(sc.cno)<(select count(distinct cno)from course)
===================================
select * from student where sno in
(select sno from
        (select stu.sno,c.cno from student stu
        cross join course c
        minus
        select sno,cno from sc)
)

11、查询至少有一门课与学号为“s001”的同学所学相同的同学的学号和姓名;

select st.* from student st,
(select distinct a.sno from
(select * from sc) a,
(select * from sc where sc.sno='s001') b
where a.cno=b.cno) h
where st.sno=h.sno and st.sno<>'s001'

12、查询至少学过学号为“s001”同学所有一门课的其他同学学号和姓名;

select * from sc
left join student st
on st.sno=sc.sno
where sc.sno<>'s001'
and sc.cno in
(select cno from sc
where sno='s001')

13、把“SC”表中“谌燕”老师教的课的成绩都更改为此课程的平均成绩;

update sc c set score=(select avg(c.score)  from course a,teacher b
                            where a.tno=b.tno
                            and b.tname='谌燕'
                            and a.cno=c.cno
                            group by c.cno)
where cno in(
select cno from course a,teacher b
where a.tno=b.tno
and b.tname='谌燕')

14、查询和“s001”号的同学学习的课程完全相同的其他同学学号和姓名;

select* from sc where sno<>'s001'
minus
(
select* from sc
minus
select * from sc where sno='s001'
)

15、删除学习“谌燕”老师课的SC 表记录;

delete from sc
where sc.cno in
(
select cno from course c
left join teacher t on  c.tno=t.tno
where t.tname='谌燕'
)

16、向SC 表中插入一些记录,这些记录要求符合以下条件:没有上过编号“c002”课程的同学学号、“c002”号课的平均成绩;

insert into sc (sno,cno,score)
select distinct st.sno,sc.cno,(select avg(score)from sc where cno='c002')
from student st,sc
where not exists
(select * from sc where cno='c002' and sc.sno=st.sno) and sc.cno='c002';

17、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分

select cno ,max(score),min(score) from sc group by cno;

18、按各科平均成绩从低到高和及格率的百分数从高到低顺序

select cno,avg(score),sum(case when score>=60 then 1 else 0 end)/count(*)
as 及格率
from sc group by cno
order by avg(score) , 及格率desc

19、查询不同老师所教不同课程平均分从高到低显示

select max(t.tno),max(t.tname),max(c.cno),max(c.cname),c.cno,avg(score) from sc , course c,teacher t
where sc.cno=c.cno and c.tno=t.tno
group by c.cno
order by avg(score) desc

20、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]

select sc.cno,c.cname,
sum(case  when score between 85 and 100 then 1 else 0 end) AS "[100-85]",
sum(case  when score between 70 and 85 then 1 else 0 end) AS "[85-70]",
sum(case  when score between 60 and 70 then 1 else 0 end) AS "[70-60]",
sum(case  when score <60 then 1 else 0 end) AS "[<60]"
from sc, course c
where  sc.cno=c.cno
group by sc.cno ,c.cname;

21、查询各科成绩前三名的记录:(不考虑成绩并列情况)

select * from
(select sno,cno,score,row_number()over(partition by cno order by score desc) rn from sc)
where rn<4

22、查询每门课程被选修的学生数

select cno,count(sno)from sc group by cno;

23、查询出只选修了一门课程的全部学生的学号和姓名

select sc.sno,st.sname,count(cno) from student st
left join sc
on sc.sno=st.sno
group by st.sname,sc.sno having count(cno)=1;

24、查询男生、女生人数

select ssex,count(*)from student group by ssex;

25、查询姓“张”的学生名单

select * from student where sname like '张%';

26、查询同名同性学生名单,并统计同名人数

select sname,count(*)from student group by sname having count(*)>1;

27、1981 年出生的学生名单(注:Student 表中Sage 列的类型是number)

select sno,sname,sage,ssex from student t where to_char(sysdate,'yyyy')-sage =1988

28、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列

select cno,avg(score) from sc group by cno order by avg(score)asc,cno desc;

29、查询平均成绩大于85 的所有学生的学号、姓名和平均成绩

select st.sno,st.sname,avg(score) from student st
left join sc
on sc.sno=st.sno
group by st.sno,st.sname having avg(score)>85;

30、查询课程名称为“数据库”,且分数低于60 的学生姓名和分数

select sname,score from student st,sc,course c
where st.sno=sc.sno and sc.cno=c.cno and c.cname='Oracle' and sc.score<60

31、查询所有学生的选课情况;

select st.sno,st.sname,c.cname from student st,sc,course c
where sc.sno=st.sno and sc.cno=c.cno;

32、查询任何一门课程成绩在70 分以上的姓名、课程名称和分数;

select st.sname,c.cname,sc.score from student st,sc,course c
where sc.sno=st.sno and sc.cno=c.cno and sc.score>70

33、查询不及格的课程,并按课程号从大到小排列

select sc.sno,c.cname,sc.score from sc,course c
where sc.cno=c.cno and sc.score<60 order by sc.cno desc;

34、查询课程编号为c001 且课程成绩在80 分以上的学生的学号和姓名;

select st.sno,st.sname,sc.score from sc,student st
where sc.sno=st.sno and cno='c001' and score>80;

35、求选了课程的学生人数

select count(distinct sno) from sc;

36、查询选修“谌燕”老师所授课程的学生中,成绩最高的学生姓名及其成绩

select st.sname,score from student st,sc ,course c,teacher t
where
st.sno=sc.sno and sc.cno=c.cno and c.tno=t.tno
and t.tname='谌燕' and sc.score=
(select max(score)from sc where sc.cno=c.cno)

37、查询各个课程及相应的选修人数

select cno,count(sno) from sc group by cno;

38、查询不同课程成绩相同的学生的学号、课程号、学生成绩

select a.* from sc a ,sc b where a.score=b.score and a.cno<>b.cno

39、查询每门功课成绩最好的前两名

select * from (
select sno,cno,score,row_number()over(partition by cno order by score desc) my_rn from sc t
)
where my_rn<=2

40、统计每门课程的学生选修人数(超过10 人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

select cno,count(sno) from sc group by cno
having count(sno)>10
order by count(sno) desc,cno asc;

41、检索至少选修两门课程的学生学号

select sno from sc group by sno having count(cno)>1;
||
select sno from sc group by sno having count(sno)>1;

42、查询全部学生都选修的课程的课程号和课程名

select distinct(c.cno),c.cname from course c ,sc
where sc.cno=c.cno
||
select cno,cname from course c
where c.cno in
(select cno from sc group by cno)

43、查询没学过“谌燕”老师讲授的任一门课程的学生姓名

select st.sname from student st
where st.sno not in
(select distinct sc.sno from sc,course c,teacher t
where sc.cno=c.cno and c.tno=t.tno and t.tname='谌燕')

44、查询两门以上不及格课程的同学的学号及其平均成绩

select sno,avg(score)from sc
where sno in
(select sno from sc where sc.score<60
group by sno having count(sno)>1
) group by sno

45、检索“c004”课程分数小于60,按分数降序排列的同学学号

select sno from sc where cno='c004' and score<90 order by score desc;

46、删除“s002”同学的“c001”课程的成绩

delete from sc where sno='s002' and cno='c001';



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