正则表达式与运用

1 #!/bin/bash
2 
3 str="date:2017-11-28 os:centos blackbord:blog"
4 
5 echo $str | grep centos --color
6 echo $str | grep -oE centos --color
7 #组的使用
8 echo $str | sed -rne 's/.*(date:[0-9]{4}-[0-9]{2}-[0-9]{2}).*(blackbord:[a-z]+).*/group:\1 group:\2/p'

1 date:2017-11-28 os:centos blackbord:blog
2 centos
3 group:date:2017-11-28 group:blackbord:blog

 1 #coding=utf-8
 2 import re
 3 
 4 str1="line:20 date(2017-11-28) os:centos blackbord[blog] last"
 5 
 6 matchobj = re.search("(date\(\d+-\d+-\d+\)).*(os:[a-z]+).*(blackbord\[[a-z]+\])", str1)
 7 if matchobj:
 8     num = len(matchobj.groups())
 9     print "match_len:" + str(num)
10     print matchobj.groups()
11 
12     date = matchobj.group(1)    #date(2017-11-28)
13     date = date[5:len(date)-1]
14     os = matchobj.group(2)  #os:centos
15     os = os[3:]
16     blackbord = matchobj.group(3)   #blackbord[blog]
17     blackbord = blackbord[10:len(blackbord) -1 ]
18     print("date:%s\nos:%s\nblackbord:%s" % (date, os, blackbord))
19 else:
20     print "not match str1"

1 match_len:3
2 ('date(2017-11-28)', 'os:centos', 'blackbord[blog]')
3 date:2017-11-28
4 os:centos
5 blackbord:blog