cout,printf的++，--优先问题

#include<iostream>
using namespace std;
int n;
class myint {
  friend ostream& operator<<(ostream& cout, myint mi);
private:
  int mynum;
  string name;
public:
  myint() {
    mynum = 0;
    name = "*********";
  }
  myint& operator++() {
    n++;
    mynum++;
    cout <<"第"<<n<<"次"<< "前置++" << endl;
    return *this;
  }
  myint& operator--() {
    n++;
    mynum--;
    cout << "第" << n << "次" << "前置--" << endl;
    return *this;
  }
  myint operator++(int) {
    n++;
    myint temp = *this;
    mynum++;
    cout << "第" << n << "次" << "后置++" << endl;
    return temp;
  }
  myint operator--(int) {
    n++;
    myint temp = *this;
    mynum--;
    cout << "第" << n << "次" << "后置--" << endl;
    return temp;
  }
};
ostream& operator<<(ostream& cout, myint me) {
  n++;
  cout <<"a="<< me.mynum << me.name <<"n="<< n<<endl;
  return cout;
}
int main() {
  myint me;
  cout << --me << me++  << me-- << ++me << endl;
  int a = 0;
}