C语言之十进制转化为十六进制

  #include <stdio.h>
  int main() {
  char  hex[17] = { "0123456789ABCDEF" };
  int  c[20], i, n, base, dec;
  printf("输入十进制正整数 ");
  scanf_s("%d", &dec);
  i = 0;  base = 16;  n = dec;
  do {
    c[i++] = dec % base;
    dec = dec/base;
  } while (dec);
  printf("%d对应的十六进制数是:", n);
  for (--i; i >= 0; i--)
    printf("%c", hex[c[i]]);
  printf("\n");
  return 0;
}

520

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