1028 List Sorting
Excel can sort records according to any column. Now you are supposed to imitate this function.
Input Specification:
Each input file contains one test case. For each case, the first line contains two integers N (≤105) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student’s record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).
Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID’s; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID’s in increasing order.
Sample Input 1:
3 1 000007 James 85 000010 Amy 90 000001 Zoe 60
Sample Output 1:
000001 Zoe 60 000007 James 85 000010 Amy 90
Sample Input 2:
4 2 000007 James 85 000010 Amy 90 000001 Zoe 60 000002 James 98
Sample Output 2:
000010 Amy 90 000002 James 98 000007 James 85 000001 Zoe 60
Sample Input 3:
4 3 000007 James 85 000010 Amy 90 000001 Zoe 60 000002 James 9
Sample Output 3:
000002 James 9 000001 Zoe 60 000007 James 85 000010 Amy 90
题意
第一行给定学生人数 N 和序号 C 。
按照给定序号数对学生进行排序:
如果 C = 1 ,则按照 ID 升序的顺序排序。
如果 C = 2 ,则按照名称以不降序的顺序排序。
如果 C = 3 ,则按照成绩以不降序的顺序排序。
当出现学生名字相同或是成绩相同的情况时,按照 ID 升序的顺序,对他们进行排序。
思路
- 用结构体数组存储学生信息,注意要用
scanf
输入,这题数据量比较大,用cin
会超时。 - 分别设定三个比较函数,然后根据给定的
C
值进行对应的排序。 - 输出排序后的结果。
代码
#include<bits/stdc++.h> using namespace std; const int N = 100010; struct Student { string id, name; int grade; }all[N]; //按照id升序排序 bool cmp1(Student& s1, Student& s2) { return s1.id < s2.id; } //按照名字升序排序 bool cmp2(Student& s1, Student& s2) { if (s1.name != s2.name) return s1.name < s2.name; return s1.id < s2.id; } //按照成绩升序排序 bool cmp3(Student& s1, Student& s2) { if (s1.grade != s2.grade) return s1.grade < s2.grade; return s1.id < s2.id; } int main() { int n, c; scanf("%d %d", &n, &c); //输入学生信息 char id[10], name[10]; for (int i = 0; i < n; i++) { int grade; scanf("%s %s %d", &id, &name, &grade); all[i] = { id,name,grade }; } if (c == 1) sort(all, all + n, cmp1); //按照id升序排序 else if (c == 2) sort(all, all + n, cmp2); //按照名字升序排序 else sort(all, all + n, cmp3); //按照成绩升序排序 //输出排序结果 for (int i = 0; i < n; i++) printf("%s %s %d\n", all[i].id.c_str(), all[i].name.c_str(), all[i].grade); return 0; }