2 2 1
1 1 2 2
1 2

1

import java.io.IOException;
import java.io.InputStreamReader;
import java.io.StreamTokenizer;
public class Main {
    static int n;
    static int m;
    static int N = 10;
    static int T;
    static int[][] arr = new int[N][N];
    static boolean[][] vis = new boolean[N][N];
    static int[][] dir = {{1,0}, {-1,0}, {0,1}, {0,-1}};
    static int res = 0;
    static int x0;
    static int y0;
    static int x;
    static int y;
    public static void main(String[] args) throws IOException {
        Read read = new Read();
        n = read.nextInt();
        m = read.nextInt();
        T = read.nextInt();
        // (x0,y0) -> 起始点坐标
        // (x,y) -> 终点坐标
        x0 = read.nextInt();
        y0 = read.nextInt();
        x = read.nextInt();
        y = read.nextInt();
        for (int i = 1 ; i <= n; i++) {
            for (int j =  1; j <= m; j++) {
              // 赋予默认值1
                arr[i][j] = 1;
            }
        }
        for (int k = 1 ; k <= T; k++) {
          // 标记障碍物为0
            int a1 = read.nextInt();
            int a2 = read.nextInt();
            arr[a1][a2] = 0;
        }
        dfs(x0,y0);
        System.out.println(res);
    }
    public static void dfs(int i,int j) {
      // 如果到达终点退出循环
        if (i == x && j == y) {
            res++;
            return;
        } else {
          // 针对(i,j)坐标每次进行上下左右的探索
            for (int k = 0 ; k < 4; k++) {
                int dx = i + dir[k][0];
                int dy = j + dir[k][1];
                // 如果当前坐标(dx,dy)没有被访问过，且(dx,dy)是非障碍物点
                if (dx >= 1 && dx <= n && dy >= 1 && dy <= m && arr[dx][dy] == 1 && !vis[dx][dy]) {
                  // 标记(i,j)已经遍历过
                    vis[i][j] = true;
                    dfs(dx, dy);
                    // 还原(i,j)
                    vis[i][j] = false;
                }
            }
        }
    }
}
class Read {
    StreamTokenizer st = new StreamTokenizer(new InputStreamReader(System.in));
    public int nextInt() throws IOException {
        st.nextToken();
        return (int) st.nval;
    }
    public double nextDouble() throws IOException {
        st.nextToken();
        return st.nval;
    }
    public String nextString() throws IOException {
        st.nextToken();
        return st.sval;
    }
}